All categories

3 years ago

What is the inverse of the given function? y = 3x 9

Mathematics

2 answers:

lakkis [162]3 years ago

6 0

Y = 3x + 9
3x = y - 9
x = 1/3 y - 3
Inverse is y = 1/3x - 3

BaLLatris [955]3 years ago

5 0

Answer:

Step-by-step explanation:

The given equation is y=3x+9.

To find the inverse of the function we switch x and y then solve for y .This will give us the inverse of the function.

Switching x and y in the given equation we have :

x=3y+9.

Adding 9 both sides :

x-9=3y.

With y term 3 is multiplied .Dividing both sides by 3 we have:

$\frac{x}{3} -3=y$

Or $y=\frac{1}{3} x-3$

You might be interested in

The amount of water in a barrel decreased is 9 5/8 pints in 7 weeks

gizmo_the_mogwai [7]

Answer:

1 3/8 in one week

Step-by-step explanation:

3 0

2 years ago

Help me wit dis plz for for 20 points

Alisiya [41]

Answer:

I dont know but combine like terms and then solve it will make It alot easier

5 0

2 years ago

PLEASE HELP EM THANKS Solve |c - 2| = 10.

yKpoI14uk [10]

$|c-2|=10\\
c-2=10 \vee c-2=-10\\
c=12 \vee c=-8$

4 0

2 years ago

I reallyyy need help... this is due today And I don’t know how to do it

olga_2 [115]

The picture is super blurry so i can’t see anything

7 0

2 years ago

[(1/(3+x))-(1/3)] / x<br> Limit 0

Effectus [21]

First find a common denominator and combine the fractions in the numerator:

$\displaystyle\lim_{x\to0}\frac{\dfrac1{3+x}-\dfrac13}x=\lim_{x\to0}\frac{\dfrac3{3(3+x)}-\dfrac{3+x}{3(3+x)}}x=\lim_{x\to0}\frac{3-(3+x)}{3x(3+x)}$

Now simplify and cancel out all the terms that you can:

$\displaystyle\lim_{x\to0}\frac{3-3-x}{3x(3+x)}=-\frac13\lim_{x\to0}\frac1{3+x}$

Since the remaining expression is continuous as a function of $x$ , you can directly substitute to end up with

$\displaystyle-\frac13\lim_{x\to0}\frac1{3+x}=-\frac13\times\frac1{3+0}=-\frac19$

8 0

2 years ago