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Zarrin [17]
3 years ago
7

There were 9068 people at a concert. An equal number of people sat in each of 4 sections. How many people sat in each section?

Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0
You divide 9068 by 4 (sections), you will then get 2267
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Evaluate v(x)=12-2x-5 when x=-2,0, and 5 .<br><br> v(-2)= <br><br> v(0)= <br><br> v(5)=
Vaselesa [24]

Step-by-step explanation:

v(-2)= 12-2x(-2)-5

=12+4-5

=16-5

=11

v(0)= 12-2x0-5

= 12-0-5

=12-5

=7

v(5)= 12-2x5-5

= 12-10-5

=12-5

=7

<em><u>Hope </u></em><em><u>it </u></em><em><u>helps </u></em>

6 0
1 year ago
Ted and Jude are each saving money each month. After x months, the amount of money, in dollars, that Ted has saved is represente
Nadusha1986 [10]

Answer:

True Statements are -

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

Step-by-step explanation:

Given - Ted and Jude are each saving money each month. After x months, the amount of money, in dollars, that Ted has saved is represented by the

equation T = 40x, and the amount of money that Jude has saved is represented by the equation J = 60x.

To find - Choose all of the statements that are true.

A. Each month, Jude saves two-thirds as much money as Ted saves.

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

C. The amount of money Jude saves each month is $20 more than the amount Ted saves each month.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

Proof -

Given that,

After x months,

Ted saved the amount of money, T(x) = 40x

Jude saved the amount of money, J(x) = 60x

Now,

In 1 month,

Ted saved money, T(1) = 40(1) = 40

Jude saved money, J(1) = 60(1) = 60

So,

In 1st month, Jude saved money 20 more than Ted saved.

Now,

In 2 month,

Ted saved money, T(2) = 40(2) = 80

Jude saved money, J(2) = 60(2) = 120

So,

In 2nd month, Jude saved money 40 more than Ted saved.

Now,

In 3 month,

Ted saved money, T(3) = 40(3) = 120

Jude saved money, J(3) = 60(3) = 180

So,

In 3rd month, Jude saved money 60 more than Ted saved.

So,

Option C is incorrect

Because

In 1st month, Jude saves  is $20 more than the amount Ted saves

In 2nd month, Jude saves  is $40 more than the amount Ted saves

Now,

In 1st month,

Ted saves = 40

and

\frac{2}{3}(40) = 26.67

So, Jude will save = 40 + 26.67 = 66.67

But Jude saves 60

So,

Option A is incorrect.

i.e. A. Each month, Jude saves two-thirds as much money as Ted saves.

Now,

We can see that,

In 3 months, Ted will have saved the money = 120

In 2 months, Jude will have saved the money = 120

So,

Option B is correct.

i.e. B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

Also,

We can see that

In 1st month, Jude saved money 20 more than Ted saved.

In 2nd month, Jude saved money 40 more than Ted saved.

In 3rd month, Jude saved money 60 more than Ted saved.

So,

Option D is correct.

i.e. D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

∴ we get

True Statements are -

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

7 0
2 years ago
These two are messing with me, can someone help?
soldier1979 [14.2K]

Answer:

i dont understand, can you elaborate

Step-by-step explanation:

7 0
2 years ago
Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value
algol [13]

Answer:

Minimum value of function C=x+10y is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

                                   C=x+10y

Subject to constraints:

                                   x\leq 3---(1)\\y\leq 9---(2)\\x+y\geq 9----(3)\\x\geq 0\\y\geq 0

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering x+y\geq 9, corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

                                    C=x+10y

at A(0,9)

                                     C=0+10(9)\\C=90

at B(3,9)

                                     C=3+10(9)\\C=93

at C(3,6)

                                     C=3+10(6)\\C=63

Minimum value of function C=x+10y is 63 occurs at point C (3,6).

3 0
3 years ago
What is the distance between these set of points?<br> (-2,-3) and (3,4)
goldenfox [79]

Step-by-step explanation:

apply distance formula

distance = ±√(4--3)^2 + (3--2)^2 = ±√74 (rej - value since distance > 0)

Topic: coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

4 0
2 years ago
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