Answer: The first ten terms are;
-10, -12, -14, -16, -18, -20, -22, -24, -26 and -28
Step-by-step explanation:
This sequence will be an arithmetic sequence since they have a "common difference".
The nth term of a sequence is
Tn = a+(n-1)d
a is the first term = -10
n is the number of terms
d is the common difference = -2
Second term is when n= 2
T2 = a+d
T2 = -10-2 = -13
When n= 3
T3 = a+2d
T3 = -10 + 2(-2)
T3 = -10 -4
T3 = -14
When n=4
T4 = a+3d
T4 = -10 +3(-2)
T4 = -10 - 6
T4 = -16
When n = 5
T5 = a+4d
T5 = -10 + 4(-2)
T5 = -10-8
T5 = -18
When n=6
T6 = a+5d
T6 = -10+5(-2)
T6 = -10-10
T6 = -20
When n= 7
T7 = a+6d
T7 = -10+6(-2)
T7 = -10-12
T7 = -22
When n= 8
T8 = a+7d
T8 = -10+7(-2)
T8 = -10-14
T8 = -24
When n= 9
T9 = a+8d
T9 = -10+8(-2)
T9 = -10-16
T9 = -26
When n= 10
T10 = a+9d
T10 = -10+9(-2)
T10 = -10 - 18
T10 = -28
Therefore the first ten terms are;
-10, -12, -14, -16, -18, -20, -22, -24, -26 and -28
