Answer:
So a point is (-3,-5) and the vertex is (-4,-3)
Step-by-step explanation:
This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.
The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)
I will choice -3. This gives -2(-3+4)^2-3
f(-3)=-2(1)^2-3
f(-3)=-2-3
f(-3)=-5
So a point is (-3,-5) and the vertex is (-4,-3)
Answer:
19is the answer I think so please check it iam sorry
Answer:
A. 
Step-by-step explanation:
We are given the expression, 
On re-writing the expression after borrowing 1, we have,
=
i.e.
= 
i.e.
= 
Thus, the equivalent expression after borrowing 1 from the given expression is
.
Hence, option A is correct.
Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:
y= -2x
Step-by-step explanation:
The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.
Given that the slope is -2, m= -2.
subst. m= -2 into the equation:
y= -2x +c
To find the value of c, substitute a coordinate.
When x= -4, y=8,
8= -2(-4) +c
8= 8 +c (expand)
c= 8-8 (-8 on both sides)
c=0 (simplify)
Thus, the equation of the line is y= -2x.