
solve for "k", to find k or the "constant of variation"
then plug k's value back to

now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is
Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
New price = A
The formula used will be:

Using the values, we get:
Thus, the worth of Suzuki after 3 years will be $8951.70
We are given
△ABC, m∠A=60° m∠C=45°, AB=8
Firstly, we will find all angles and sides
Calculation of angle B:
we know that sum of all angles is 180
m∠A+ m∠B+m∠C=180
we can plug values
60°+ m∠B+45°=180
m∠B=75°
Calculation of BC:
we can use law of sines

now, we can plug values



Calculation of AC:

now, we can plug values



Perimeter:

we can plug values


Area:
we can use formula

now, we can plug values

...............Answer
Answer:
D. 105 students and 150 guests
Step-by-step explanation:
105 students and $1 for each ticket is $105.(105 x 1 = 105)
150 guests and $5 for each ticket is $750.(150 x 5 =750)
$105 + $750 = $855
Answer:
q≤7
Step-by-step explanation:
q+8≤15
1) Subtract 8 from both sides:
q≤7