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lesya [120]
3 years ago
9

How many solutions are there for this graph? Select one: a. 3 b. 2 c. 1 d. 0

Mathematics
1 answer:
drek231 [11]3 years ago
7 0
The graph intersects the x-axis at 2 points, therefore there are 2 values of x for which y = 0, meaning there are 2 solutions.
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Svetradugi [14.3K]
The answer is 7 multiple by 10 =70
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3 years ago
What is (6.5) squared​
charle [14.2K]
Answer :
4.25


Step-by-step explanation :


Hope it helped you :)
8 0
3 years ago
Read 2 more answers
The area of the isosceles triangle is 80 square centimeters. Use the equation 1/2(8h) =80 to find the height of the triangle.
Dmitry [639]

Answer:

20cm

Step-by-step explanation:

Given data

Area=  80cm^2

we know that the expression for the area of a triangle is

A= 1/2B*H

from the given expression 1/2(8h) =80 the base is 8cm

let us substitute to find the height h

1/2(8h) =80

4h=80

h= 80/4

h= 20cm

Hence the heigth h is 20cm

6 0
2 years ago
Item 3 Find the distance from point $A$ to $\overleftrightarrow{XZ}$ . Round your answer to the nearest tenth. Triangle X Z A an
vovikov84 [41]

Answer:

3.2

Step-by-step explanation:

Given the coordinates

X(4, -3)

Y(2, 1.5)

A(3, 3)

Z(4,-1)

We are to find the distance from point A to XZ

First let us get the coordinate XZ

According to vector notation XZ = Z-X

XZ = (4,-1)-(4,-3)

XZ = [(4-4),-1-(-3)]

XZ = (0, 2)

Next is to find the distance from A(3, 3) to XZ(0,2) using the formula for calculating the distance between two points.

D = √(x2-x1)²+(y2-y1)²

x1 = 3, y1 = 3, x2 = 0, y2 = 2

D = √(0-3)²+(2-3)²

D = √9+1

D = √10

D = 3.16

Hence the distance from point A to XZ to nearest tenth is 3.2

4 0
3 years ago
A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The
alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

d(t)=-16t^2+48t+160

t is the time

d(t) is the distance traveled

Initial height is 160 feet and initial velocity is 48 ft/sec

If we want to find the time it takes the ball to hit the ground, we let d(t) equal to 0 and find t. Shown below:

-16t^2+48t+160=0\\t^2-3t-10=0\\(t-5)(t+2)=0\\t=5,-2

We disregard t = -2 since time can't be negative. We take t = 5

Thus, after 5 seconds, the ball strikes the ground.

The equation is a quadratic of the form: ax^2+bx+c

Matching equations, we can say:

a = -16

b = 48

c = 160

The time when ball reaches max height is given as:

t=-\frac{b}{2a}

Substituting, we find:

t=-\frac{b}{2a}\\t=-\frac{48}{2(-16)}\\t=1.5

The ball reaches maximum height at t = 1.5 seconds

The max height can be found by putting t = 1.5 into the original equation. Shown below:

d(t)=-16t^2+48t+160\\d(1.5)=-16(1.5)^2+48(1.5)+160\\=196

The max height is 196 feet

8 0
3 years ago
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