Factor. 16x^2+40x+25
2 answers:
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A) There are a number of ways to compute the determinant of a 3x3 matrix. Since k is on the bottom row, it is convenient to compute the cofactors of the numbers on the bottom row. Then the determinant is ...
1×(2×-1 -3×1) -k×(3×-1 -2×1) +2×(3×3 -2×2) = 5 -5k
bi) Π₁ can be written using r = (x, y, z).
Π₁ ⇒ 3x +2y +z = 4
bii) The cross product of the coefficients of λ and μ will give the normal to the plane. The dot-product of that with the constant vector will give the desired constant.
Π₂ ⇒ ((1, 0, 2)×(1, -1, -1))•(x, y, z) = ((1, 0, 2)×(1, -1, -1))•(1, 2, 3)
Π₂ ⇒ 2x +3y -z = 5
c) If the three planes form a sheath, the ranks of their coefficient matrix and that of the augmented matrix must be 2. That is, the determinant must be zero. The value of k that makes the determinant zero is found in part (a) to be -1.
A common approach to determining the rank of a matrix is to reduce it to row echelon form. Then the number of independent rows becomes obvious. (It is the number of non-zero rows.) This form for k=-1 is shown in the picture.
1×(2×-1 -3×1) -k×(3×-1 -2×1) +2×(3×3 -2×2) = 5 -5k
bi) Π₁ can be written using r = (x, y, z).
Π₁ ⇒ 3x +2y +z = 4
bii) The cross product of the coefficients of λ and μ will give the normal to the plane. The dot-product of that with the constant vector will give the desired constant.
Π₂ ⇒ ((1, 0, 2)×(1, -1, -1))•(x, y, z) = ((1, 0, 2)×(1, -1, -1))•(1, 2, 3)
Π₂ ⇒ 2x +3y -z = 5
c) If the three planes form a sheath, the ranks of their coefficient matrix and that of the augmented matrix must be 2. That is, the determinant must be zero. The value of k that makes the determinant zero is found in part (a) to be -1.
A common approach to determining the rank of a matrix is to reduce it to row echelon form. Then the number of independent rows becomes obvious. (It is the number of non-zero rows.) This form for k=-1 is shown in the picture.
Answer:
Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3.
Step-by-step explanation:
The rectangle ABCD is dilated by a factor of 3 to get the rectangle WXYZ whose area is found to be 72 cm².
Let the dimensions of the dilated rectangle WXYZ are a cm by b cm.
So, ab = 72 ........... (1)
Now, the dimensions of the original rectangle are 3 times lesser than the dimensions of rectangle WXYZ.
So, the area of rectangle ABCD will be cm² {from equation (1)}
Therefore, Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3. (Answer)
<h3>Answer: Choice C</h3>
Started in Quadrant II and ended in Quadrant IV.
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Explanation:
Refer to the diagram below. It shows how the four quadrants are labeled using roman numerals. We start in the upper right corner (aka northeast corner) and work counterclockwise when labeling quadrant I, II, III, and IV in that order.
The green point A is located in quadrant II in the northwest. Meanwhile point B in red is in the southeast quadrant IV.
Therefore, we started in <u>quadrant II</u> and ended in <u>quadrant IV</u> which points us to <u>choice C.</u>