All categories

4 years ago

What is 10y-3x+6=11 in standard form

1 answer:

3 0

Standard form for linear equations is Ax+By=C

10y-3x=5
-3x+10y=5....But "A" can't be negative ( or a fraction) so multiply each by -1

-1(-3x+10y=5)
Answer= 3x-10y=-5

You might be interested in

A "child has six blocks, three of which are red and three of which are green". How many patterns can shemake by placing them all

makvit [3.9K]

Answer: There are 20 ways and 1680 ways respectively.

Step-by-step explanation:

Since we have given that

Total number of blocks = 6

Number of red blocks = 3

Number of green blocks = 3

So, Number of patterns she can make by placing them all in a line is given by

$\dfrac{6!}{3!\times 3!}\\\\=20$

If there are 3 white blocks

so, total number of white blocks becomes 9

So, Number of total pattern she can make by placing all nine blocks in a line is given by

$\dfrac{9!}{3!\times 3!\times 3!}\\\\=1680\ ways$

Hence, there are 20 ways and 1680 ways respectively.

6 0

4 years ago

In the xy -coordinate plane, the coordinates of point s are (-2,-6), and coordinates of point T are (18,9). Point Q lies on line

ira [324]

Answer:

(6,0)

Step-by-step explanation:

The coordinates of the points dividing the line segment in ratio m:n can be calculated as:

$(\frac{mx_{2}+nx_{1}}{m+n} ,\frac{my_{2}+ny_{1}}{m+n} )$

Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).

In this case m will be 2 and n will be 3 as the ratio is 2:3

Using all these values we can find the coordinates of point Q

$( \frac{2(18)+3(-2)}{2+3},\frac{2(9)+3(-6)}{2+3} )\\\\ = (\frac{30}{5} ,\frac{0}{5} )\\\\ =(6,0)$

Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)

5 0

3 years ago

Can anyone solve this for me???

Elena-2011 [213]

Answer:

Step-by-step explanation:

It x

5 0

3 years ago

if the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expressi

Softa [21]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, 6 ), thus

y = a(x + 4)² + 6

To find a substitute (- 3, 14) into the equation

14 = a(- 3 + 4)² + 6 ( subtract 6 from both sides )

8 = a

Thus the coefficient of the x² term is a = 8

3 0

3 years ago

Please write the answer

Travka [436]

$\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\ \\ \longrightarrow \sf \: 27 - 15 \\ \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}$

6 0

3 years ago