Answer: At 6% = $66,800
At 10% = $34,400
Step-by-step explanation:
Let S be his savings. He divided S into x that goes at 6% and y at 10%
As he put twiced as much at the lower-yielding one, x = 2y
Simple interest is given by: Amount x interest x time
This way I₁ = x . 0.06 . 1 = 0.06x
I₂ = y. 0.10 . 1 = 0.10y
As x = 2y, I₁ = = 0.06 . 2y = 0.12y
As we know that the annual interest was $7348
I₁ + I₂ = 7348
0.12y + 0.10y = 7348
0.22y = 7348
y = 7348/0.22
y = 33,400
As x = 2y, x = 2.33,400 = 66,800
This was he invested $33,400 and $66,800
F=v+at
f-v=at
(f-v)/t =a
the first choice is correct :)
<span>the answer is b. V = 396 - 5x; $341</span>
