What is the partial pressure of 0.50 mol Ne gas combined with 1.20 mol Kr gas at a final pressure of 730 torr?

2 answers:

8 0

The partial pressure of 0.50 Ne gas is 214.71 torr

calculation

the partial pressure of Ne = moles of Ne/total moles x final pressure

find the total moles of the air mixture

that is moles of Ne + moles of K= 0.50 + 1.20 = 1.70 moles

The partial pressure is therefore = 0.50 /1.70 x 730 = 214.71 torr

Scorpion4ik [409]3 years ago

3 0

it would be 215 torr for the answer for edg

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