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aleksandr82 [10.1K]
3 years ago
10

In nuclear physics what units are used to measure the radius of an Atom

Chemistry
1 answer:
Paul [167]3 years ago
7 0
I'm sorry I'm not quit sure
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Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water
Romashka [77]
The balanced reaction is 
Na2O + H2O --> 2NaOH

If 2.24 moles of sodium oxide react, that means 4.48 moles of NaOH is formed as it is a 1 to 2 stoichiometric relationship.

Now we multiply by the molar mass to get grams.

4.48 moles NaOH * (39.997 grams/1 mole) = 179.2 grams

Your answer is 179. grams.
6 0
3 years ago
Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12




3 0
3 years ago
Why can water be used in the cooling system of a car? A. it always heats the car in the winter B. it helps fluctuate temperature
JulsSmile [24]
The answer is C. It resists fast temperature change
8 0
3 years ago
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What is the energy change associated with 1.5 mole of D being formed? 
AleksandrR [38]

Answer:

–36 KJ.

Explanation:

The equation for the reaction is given below:

2B + C —› D + E. ΔH = – 24 KJ

From the equation above,

1 mole of D required – 24 KJ of energy.

Now, we shall determine the energy change associated with 1.5 moles of D.

This can be obtained as illustrated below:

From the equation above,

1 mole of D required – 24 KJ of energy

Therefore,

1.5 moles of D will require = 1.5 × – 24 = –36 KJ.

Therefore, –36 KJ of energy is associated with 1.5 moles of D.

3 0
2 years ago
The term gas is limited to those substances that exist in the gaseous state at
Assoli18 [71]
Physical change alters a given material without changing its chemical.
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2 years ago
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