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aleksandr82 [10.1K]
3 years ago
10

In nuclear physics what units are used to measure the radius of an Atom

Chemistry
1 answer:
Paul [167]3 years ago
7 0
I'm sorry I'm not quit sure
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The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas
Roman55 [17]

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm

Density is equal to mass per unit volume.

d=\dfrac{m}{V}

m is mass of the cylinder

V is the volume of the cylinder

V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3

So,

m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g

So, the mass of the cylinder is 1.51 grams.

5 0
4 years ago
How would you build a model that is ionized? what happens if an atom is too ionized? how would you build a model that is radioac
tatyana61 [14]
It will probably zip far from you and join itself to an adjacent molecule or atom. it gets to be distinctly radioactive when its core contains an excessive number of or an excessively couple of neutrons. Attempt to keep an indistinguishable number of neutrons and protons from you construct your iota. In the event that the awkwardness is excessively extraordinary, radioactive rot will happen.
6 0
4 years ago
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC
diamong [38]

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 25^oC=273+25=298K

V = volume = 4.0 L

n_1 = moles of SO_2 = 0.20 mol

n_2 = moles of O_2 = 0.20 mol

Now put all the given values in the above expression, we get:

P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}

P=2.4atm

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0
3 years ago
A 10.-liter flask at a given temperature and pressure contains 6.0 × 1023 molecules of hydrogen gas. Under the same conditions o
valentina_108 [34]

Answer:

The same number of molecules, 6.0 × 10²³ molecules.

Explanation:

The amount of any given gas that can be stored in a container depends on the <u>temperature, pressure and volume </u>of the container. It does not depend on the nature (or identity) of the gas.

So if a 10-liter flask contains 6.0 × 10²³ molecules of hydrogen gas, it will contain the same amount of molecules of any other gas when temperature and pressure remain constant.

6 0
3 years ago
Someone please help me and answer my question asap. i need to turn my assignment in soon... please.
Ksenya-84 [330]

Answer:

Explanation:

a. the salt produced would be Mg3N2(magnesium nitride)

b. magnesium loses 2 electron to form Mg2+ ion and nitrogen gains 3 electron to form n3-

when several of these ions come together 3 Mg2+ ion combine with 2 n3- ion to form Mg3N2 thus Mg getting six electron from nitrogen to form a ionic bond.

c. the reaction is not balanced Mg + N2 = Mg3n2

to make it balanced the reaction should be 3 Mg + N2 = Mg3N2.

the reaction was not balanced before because the number of Mg on both side of the reaction was not equal.

d. magnesium nitrate has formula Mg(NO3)2 is formed when Mg combines with nitrogen and oxygen Mg + N2 + o2

8 0
3 years ago
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