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Simora [160]
3 years ago
13

Help please! the picture is below!

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0
The answer would be B
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How to solve this for x
timama [110]

the answer is x= 10.

the steps would go like this.

4 + 3/5 × (15 + 2x) = 25

4 + 9 + 6/5x = 25

13 + 6/5x = 25

65 + 6x = 125

6x = 125 -65

6x = 60

x = 10

hope this helps



5 0
3 years ago
What is 5x^2+11x+2 factored
Alina [70]

Answer:

(x+2) (5x)

Step-by-step explanation:

the way I factor is the products of a*c added together equals b. so the products if (5*2) 10 equals 11. so 10 and 1 are the 2 products that add into 11. Now we put that into the equation. 5x^2+10x+1x+2 now take the two haves until you can't factor them any more 5x(x+2) (x+2). now take the repeated factor and outside factors to get (5x) and (x+2)

4 0
3 years ago
A sum of money is invested at 12% compounded quarterly. About how long will it take for the amount of money to double?
iVinArrow [24]
I'll use my own formula (similar to yours tho)

A=P(1+ \frac{r}{n})^{nt}
A=future amount
p=invested
r=rate in decimal
n=number of times per year compounded
t=time in years


so
when will A=2P
subsitute 2P for A
also quarterly means 4 times a year or n=4
and 12%=0.12=r
so

2P=P(1+ \frac{0.12}{4})^{(4*t)}
divide both sides by P
2=(1+ \frac{0.12}{4})^{(4*t)}
simplify
2=(1+ 0.03)^{4t}
2=(1.03)^{4t}
take the ln of both sides
ln(2)=ln(1.03)^{4t}
ln(2)=4tln(1.03)
ln(2)=t(4ln(1.03))
divide both sides by 4ln(1.03)
\frac{ln(2)}{4ln(1.03)}=t
use calculator
5.86244=t
about 5.9 years
4 0
3 years ago
Read 2 more answers
If i spent $7.00 and I knew that was 12% of my savings how much savings did I have
IceJOKER [234]
X=$58.33 amount of saving
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%283x%20%2B%204%29%20%20-%207%20log_%7B4%7D%7Bx%7D%5E%7B2%7D%20%20%2B%20%20log_%
olga2289 [7]

First of all, we need all logarithms to have the same base. So, we use the formula

\log_a(b)=\dfrac{\log_c(b)}{\log_c(a)}

To change the second term as follows:

\log_4(x^2)=\dfrac{\log_2(x^2)}{\log_2(4)}=\dfrac{\log_2(x^2)}{2}

Finally, using the property

\log(a^b)=b\log(a)

we have

\dfrac{\log_2(x^2)}{2}=\log_2(x)

So, the equation becomes

\log_2(3x+4)-7\log_2(x)+\log_2(x)=2 \iff \log_2(3x+4)-6\log_2(x)=2

We can now use the formula

\log(a)-\log(b)=\log\left(\dfrac{a}{b}\right)

to write the equation as

\log_2(3x+4)-6\log_2(x)=2 \iff \log_2(3x+4)-\log_2(x^6)=2 \iff \log_2\left(\dfrac{3x+4}{x^6}\right)=2

Now consider both sides as exponents of 2:

\dfrac{3x+4}{x^6}=4 \iff 4x^6-3x-4=0

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be

5 0
3 years ago
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