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bearhunter [10]

3 years ago

9

Sandy is ordering donuts for the cafeteria. She has a budget of $100. If each donut costs Sandy $0.15, and the donut shop charge

s a $30 service fee, which inequality below represents the maximum number of donuts she can buy?

1 answer:

murzikaleks [220]3 years ago

7 0

Answer:

0.15x + 30 ≤ 100

0.15x ≤ 70

Step-by-step explanation:

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A sum has five addends. Each addend is a unit fraction. The sum is 1. What are the addends?

Bogdan [553]

I would assume 1/5 is your answer. As 1/5+1/5+1/5+1/5+1/5 = 5/5 which is 1.

4 0

3 years ago

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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

gladu [14]

Sum:

3x^5*y - 2x^3*y^4 - 7x*y^3
+ -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
-5x^5y - 6xy^3

Term 1: Degree = 6
Term 2: Degree = 4

Difference:

3x^5*y - 2x^3*y^4 - 7x*y^3
- -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
11x^5y - 4<span>x^3*y^4 - 8</span>xy^3

Term 1: Degree = 6
Term 2: Degree = 7
Term 3: Degree = 4

The degree of a term of a polynomial can be obtained by adding the exponents of the variables in that term.

5 0

3 years ago

Mr. Chaudry wants to buy a pair of shoes that costs $80. He also wants to buy some socks that are on sale for $7 each. He has $1

Vladimir [108]

Answer:

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Step-by-step explanation:

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3 years ago

Please answer the ALL of the following questions, I will give you brainliest and thanks! I want to see if you guys know it.

mario62 [17]

1) 200 candies

15% of my candies were strawberry candies. I had 30 strawberry candies. How many candies did i have?

-----

Let "x" be the number of candies.

----

Equation:

0.15x = 30

x = 30/0.15

---

Multiply numerator and denominator by 100 to get:

------------------

x = 3000/15

----

x = 200

---------------------------------

2) 146 STUDENTS

27%*T=54, So T=200.

So 200-54=146 Students passed the test.

---------------------------------

3) She got a 20% discount (or 80% discount). (Work shown for 80%).

First you have to find out how much Mandy paid. So from 15000 you will subtract 3000. 15000-3000=12000.

Next you need to set up your equation. . You then have to cross multiply. So 100 times 12000, 100*12000=1200000. And 15000 times x is 15000x. Finally you divide both sides by 15000. And 1200000 divided by 15000 is 80. X=80

Step-by-step explanation:

3 0

3 years ago

Will Mark Brainiest!!! Simplify the following:

xz_007 [3.2K]

Answer:

1.B

2.A

3. B

Step-by-step explanation:

1. $\frac{x+5}{x^{2} + 6x +5 }$

We have the denominator of the fraction as following:

$x^{2} + 6x + 5 \\= x^{2} + (1 + 5)x + 5\\= x*x + 1x + 5x + 5*1\\= x ( x + 1) + 5(x + 1)\\= (x + 1) (x + 5)$

As the initial one is a fraction, so that its denominator has to be different from 0.

=> ( $x^{2} +6x+5$ ) ≠ 0

⇔ (x +1) (x +5) ≠ 0

⇔ (x + 1) ≠ 0; (x +5) ≠ 0

⇔ x ≠ -1; x ≠ -5

Replace it into the initial equation, we have:

$\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)}$

As (x+5) ≠ 0; we divide both numerator and denominator of the fraction by (x +5)

=> $\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)} = \frac{1}{x+1}$

So that $\frac{x+5}{x^{2} + 6x +5 } = \frac{1}{x+1}$ with x ≠ 1; x ≠ -5

So that the answer is B.

2. $\frac{(\frac{x^{2} -16 }{x-1} )}{x+4}$

As the initial one is a fraction, so that its denominator has to be different from 0

=> x + 4 ≠ 0

=> x ≠ -4

As $\frac{x^{2}-16 }{x-1}$ is also a fraction, so that its denominator (x-1) has to be different from 0

=> x - 1 ≠ 0

=> x ≠ 1

We have an equation: $x^{2} - y^{2} = (x - y ) (x+y)$

=> $x^{2} - 16 = x^{2} - 4^{2} = (x -4) (x +4)$

Replace it into the initial equation, we have:

$\frac{(\frac{x^{2} -16 }{x-1} )}{x+4} \\= \frac{x^{2} -16 }{x-1} . \frac{1}{x + 4}\\= \frac{(x-4)(x+4)}{x-1}. \frac{1}{x + 4}$

As (x + 4) ≠ 0 (proven above), we can divide both numerator and the denominator of the fraction by (x +4)

=> $\frac{(x-4)(x+4)}{x-1} .\frac{1}{x+4} =\frac{x-4}{x-1}$

So that the initial equation is equal to $\frac{x-4}{x-1}$ with x ≠-4; x ≠1

=> So that the correct answer is A

3. $\frac{x}{4x + x^{2} }$

As the initial one is a fraction, so that its denominator (4x + x^2) has to be different from 0

We have:

(4x + x^2) = 4x + x.x = x ( x + 4)

So that: (4x + x^2) ≠ 0 ⇔ x ( x + 4 ) ≠ 0

⇔ $\left \{ {{x\neq 0} \atop {(x+4)\neq0 }} \right.$ ⇔ $\left \{ {{x\neq 0} \atop {x \neq -4 }} \right.$

As (4x + x^2) = x ( x + 4) , we replace this into the initial fraction and have:

$\frac{x}{4x + x^{2} } = \frac{x}{x(x+4)}$

As x ≠ 0, we can divide both numerator and denominator of the fraction by x and have:

$\frac{x}{x(x+4)} =\frac{x/x}{x(x+4)/x} = \frac{1}{x+4}$

So that $\frac{x}{4x+x^{2} } = \frac{1}{x+4}$ with x ≠ 0; x ≠ -4

=> The correct answer is B

3 0

4 years ago