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Alla [95]
4 years ago
9

What formula is MaVa=MbVb?

Chemistry
1 answer:
yawa3891 [41]4 years ago
5 0
I don't know if this helps...but it is a titration formula.
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How many valence electrons does CN1 have?
tino4ka555 [31]

7 valence electrons, because carbon has 5 electrons and nitrogen can have either 3 or 5, but because it cannot fill more than 8, we must assume those added together will equal 7

6 0
3 years ago
How many moles of nitrogen, N, are in 88.0 g of nitrous oxide, N2O?
OLga [1]
<span>Number of moles ( of N20) = mass / molar mass = 88.0g / 44.01g/mole = 2 moles So, there's 2 moles of N20, and in every molecule there's 2 nitrogen atoms -> there's 4 moles of nitrogen in 88.0g of N20</span>
3 0
4 years ago
Barium chloride emits a green color when flame tested. What can be said about the wavelength of light it emits?
spin [16.1K]

The complete question is as follows: Barium chloride (BaCl2) emits a green color when flame tested. What can be said about the wavelength of light it emits? Select all that apply.

A) The thermal energy is transferred to the outer electrons of the barium ions.

B) The electrons gain enough energy to excite them to a higher energy level.

C) The electrons drop back down to their ground state, gaining energy.

D) The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.

Answer: The following can be said about the wavelength of light that Barium chloride emits:

  • The thermal energy is transferred to the outer electrons of the barium ions.
  • The electrons gain enough energy to excite them to a higher energy level.
  • The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.

Explanation:

As barium chloride is emitting green color when flame tested. This means that thermal energy is being transferred to the outer electrons of barium ions.

A visible light is emitted by a substance when its electrons move from a region of higher energy level to lower energy level. This is because energy is given off by the electrons when they move in a lower region.

This is only possible when the electrons gain enough energy to excite them to a higher energy level.

Also, the electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.

Thus, we can conclude that following can be said about the wavelength of light that Barium chloride emits:

  • The thermal energy is transferred to the outer electrons of the barium ions.
  • The electrons gain enough energy to excite them to a higher energy level.
  • The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
5 0
3 years ago
Be sure to answer all parts. ΔH o f of hydrogen chloride [HCl(g)] is −92.3 kJ/mol. Given the following data, determine the ident
Akimi4 [234]

Answer:

NH₄Cl(s) → NH₃(g) + HCl(g)

ΔH°rxn 74,89 kJ/mol

Explanation:

The change in enthalpy of formation (ΔHf) is defined as the change in enthalpy in the formation of a substance from its constituent elements. For HCl(g):

<em>(1) </em>¹/₂H₂(g) + ¹/₂ Cl₂ → HCl(g) ΔH = -92,3 kJ/mol

It is possible to sum ΔH of different reactions to obtain ΔH of a global reaction (Hess's law).

For the reactions:

<em>(2) </em>N₂(g) + 4H₂(g) + Cl₂(g) → 2NH₄Cl(s) ΔH°rxn = −630.78 kJ/mol

<em>(3)</em> N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

The sum of -(2) + (3) gives:

<em>-(2) </em>2NH₄Cl(s) → N₂(g) + 4H₂(g) + Cl₂(g) ΔH°rxn = +630.78 kJ/mol

<em>(3)</em> N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

<em>-(2) + (3) </em>2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g)

ΔH°rxn = +630.78 kJ/mol −296.4 kJ/mol = +334,38 kJ/mol

Now, the sum of -(2) + (3) + 2×(1)

<em>-(2) + (3) </em>2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g) ΔH°rxn = +334,38 kJ/mol

<em>2×(1)  </em>H₂(g) + Cl₂(g)→ 2HCl(g) ΔH = 2×-92,3 kJ/mol

<em>-(2) + (3) + 2×(1) </em>2NH₄Cl(s) → 2NH₃(g) + 2HCl(g)

ΔH°rxn = +334,38 kJ/mol + 2×-92,3 kJ/mol = 149,78 kJ/mol

The reaction of:

<em>NH₄Cl(s) → NH₃(g) + HCl(g)</em>

<em>Has ΔH°rxn = 149,78kJ/mol / 2 = 74,89 kJ/mol</em>

I hope it helps!

8 0
3 years ago
Trying it out. help??
Black_prince [1.1K]

Answer:

tell the question also ?

5 0
2 years ago
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