Answer:
333K
Explanation:
Answer is actually 333.15, but to round it off, is 333
Answer:
Bromine (Br) loses an electron, so it is the reducing agent.
Explanation:
A reducing agent also called a reducer, is known to be an electron donor. A reducing agent is oxidized, because it loses electrons in the redox reaction.
A oxidising agent also called a oxidant or oxidiser, is known to be an electron acceptor. A oxidising agent is reduced, because it gains electrons in the redox reaction.
Cl2(aq) + 2Br-(aq) --> 2Cl-(aq) + Br2(aq)
Half ionic equations,
Cl2(aq) + 2e- --> 2Cl-(aq)
2Br-(aq) --> Br2(aq) + 2e-
Reducing agent = Br-
Oxidizing agent = Cl2
Answer:
a. alkyne
b. alkane
c. alkyne
d. alkene
Explanation:
The general formula for each class of compound is given below
Alkane:
Alkene:
Alkyne: (assuming single multiple bonds)
Now let us classify according to the above formulas:
a. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne
b. It has two hydrogen atoms more than the two times of carbon atoms hence, it's alkane
c. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne
d. It has hydrogen atoms two times of carbon atoms hence, it's alkene
C. Cleaned should be the answer