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Artist 52 [7]
2 years ago
9

Q is a solution of HCl containing 0.12 mol.dm^-3. P is a solution of Na2CO3 of unknown concentration. Solution Q was titrated ag

ainst 25.0cm^3 portions of solution P and an average titre of 26.25cm^3 was obtained. Calculate the concentration of solution P in mol.dm^-3. Na2CO3 +2HCl = 2NaCl +CO2 + H2O.​
Chemistry
1 answer:
stich3 [128]2 years ago
4 0
The correct answer to this question is HCI containing not only 0.12 but 1 whole
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A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavi
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Solution :

Using ideal gas equation,

PV=nRT\\\\PV=\frac{w}{M}\times RT

where,

n = number of moles of gas

w = mass of ammonia gas  = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas = 27^oC=273+27=300K

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

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Now put all the given values in the above equation, we get the mass of ammonia gas.

(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)

w=5.28g

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.

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