Q is a solution of HCl containing 0.12 mol.dm^-3. P is a solution of Na2CO3 of unknown concentration. Solution Q was titrated ag
ainst 25.0cm^3 portions of solution P and an average titre of 26.25cm^3 was obtained. Calculate the concentration of solution P in mol.dm^-3. Na2CO3 +2HCl = 2NaCl +CO2 + H2O.
The pH unit has 10x as many hydrogens ions as the unit above. Ex: A pH of 5 would have 10x more hydrogen ions than a pH of 6 and 100x more than if it had a pH of 7. With a pH of 9 and 3, this is equivalent to 10⁶ So your answer should be: 1,000,000
