The answer is 2.135 mol/Kg
Given that molarity is 2M, that is, 2 moles in 1 liter of solution.
Density of solution is 1.127 g/ml
Volume of solution is 1L or 1000 ml
mass of solution (m) = density × volume
m₁ = density × volume = 1.127 × 1000 = 1127 g
mass of solute, m₂ = number of moles × molar mass
m₂ = 2 × 95.211
m₂ = 190.422 g
mass of solvent = m₁ - m₂
= 1127 - 190.422
= 936.578 g
= 0.9366 Kg
molality = number of moles of solute / mass of solvent (in kg)
= 2 / 0.9366
= 2.135 mol/Kg
The answer to this question is A
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
<span>1. Use these definitions:
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i) Kinetic energy (KE) is energy in action in virtue of the motion. KE = (1/2)mv². You can tell there is KE wthen the object is moving.
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<span>ii) Potential energy (PE) is a stored energy. You notice the PE once it is transformed into another form of energy, for example into kinetic energy or heat, or light. The maing forms of potential energy are gravitational potential energy (mgh), elastic potential energy (1/2)kx², and chemical potential energy.
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</span><span>2) Answers
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1. A bicyclist pedaling up a hill: K
In virtue of the motion (speed) the byciclist has kinetic energy. Neverthelles, the pedalyst also has potential energy, which you could notice if she stops pedaling, because then she would start to go down the hill without pedaling.
</span><span>2. An archer with his bow drawn : P
</span>
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The bow will have elastic potential energy in virtue of which the arrow will be throwm as soon as the archer release it.
3. A volleyball player spiking a ball K
</span><span>The ball will have kinetic energy in virtue of its speed </span>
<span /><span>
4. A baseball thrown to second base: K
</span><span />
<span>The baseball will have kinetic energy in virtue of its speed.
</span><span />
<span>5. The chemical bonds in sugar: P
</span><span />
<span>The bonds have stored potential energy. This energy is named chemical energy. When the bonds break they release energy in the form of heat, light or sound.
6. The wind blowing over a tree: K
</span><span />
<span>The wind is moving, so it has kinetic energy. You notice the energy of the wind because it is capable to move the leaves or even the same tree, The same happens when the wind moves the blades of a windmill.
7. Walking down the street: K
</span><span />
<span>When you walk you are moving, so you have speed and that is kinetic energy.
8. Sitting at the top of a tree: P
</span><span />
<span>Sitting on a high place gives you potential energy (mgh). You potentially can suffer an injure if you fall down. The potencial energy transforms into kinetic energy when you fall down.
</span><span />
<span>9. A bowling ball rolling down the alley: K
</span><span />
<span>The ball is rotating and translating. It has angular speed and traslational speed.Both are kinetic energies.
10. A bowling ball sitting on the rack: P
</span><span />
<span>While the ball is on the rack, it has the possibility to fall down. The ball can fall off the rack and hit the floor or your foot. The stored (potential) energy can be transformed into kinetic energy.
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The doubling the amount will change the gibbs free energy as it is an extensive property which depends upon the the amount of the substance
However as asked in question the DeltaG has unit of kcal /mol
So we have already defined the amount of substance to be one mole this means the value per mole will be same irrespective of the amount taken as we are reporting it for a fixed one mole of a substance
Hence answer is
-100 kcal/mol
