Answer : The value of final volume, temperature and the work done is, 8.47 L, 258 K and -873.6 J
Explanation :
First we have to calculate the value of .
As,
So,
Given :
Now we have to calculate the initial volume of gas.
Formula used :
where,
= initial pressure of gas = 4.25 atm
= initial volume of gas = ?
= initial temperature of gas = 300 K
n = number of moles of gas = 1.0 mol
R = gas constant = 0.0821 L.atm/mol.K
Now we have to calculate the final volume of gas by using reversible adiabatic expansion.
where,
= initial pressure of gas = 4.25 atm
= final pressure of gas = 2.50 atm
= initial volume of gas = 5.80 L
= final volume of gas = ?
= 1.4
Now put all the given values in above formula, we get:
Now we have to calculate the final temperature of gas.
Formula used :
where,
= final pressure of gas = 2.50 atm
= final volume of gas = 8.47 L
= final temperature of gas = ?
n = number of moles of gas = 1.0 mol
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in above formula, we get:
Now we have to calculate the work done.
where,
w = work done = ?
n = number of moles of gas =1.0 mol
= initial temperature of gas = 300 K
= final temperature of gas = 258 K
Now put all the given values in above formula, we get:
Therefore, the value of final volume, temperature and the work done is, 8.47 L, 258 K and -873.6 J