Subtract x/x^2-36-6/x^2-36
2 answers:
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Answer:
Step-by-step explanation:
Given
(0, 1, 0)
The vector equation is given as:
Substitute values for x, y and z
Differentiate:
The parametric value that corresponds to (0, 1, 0) is:
Substitute 0 for t in r'(t)
The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)
It should be noted that:
The equation of a line through position vector a and parallel to vector v is given as:
Such that:
and
The equation becomes:
By comparison:
and
The parametric equations for the tangent line are:
