All categories

3 years ago

Give the digits in the hundred thousands place and the ten thousands place. 175,384

Mathematics

1 answer:

Lady_Fox [76]3 years ago

3 0

Hundred-thousands: 1(00,000)

Ten-thousands: 7(0,000)

I'm not sure whether or not it's asking for the full number or just the digit, but I hope I helped!

You might be interested in

If 3x + 3 = -9, then what is 3x + 5 equivalent to?

Anarel [89]

Answer:

- 7

Step-by-step explanation:

Solve for x

3x + 3 = - 9 ( subtract 3 from both sides )

3x = - 12 ( divide both sides by 3 )

x = - 4

Hence

3x + 5 = (3 × - 4) + 5 = - 12 + 5 = - 7

8 0

3 years ago

Help I need help on 4 help me as soon as possible and show me the equation

levacccp [35]

I think the equation would be

10,000 - ( 150/sec)

4 0

3 years ago

The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard de

qaws [65]

Answer: a. 0.6759 b. 0.3752 c. 0.1480

Step-by-step explanation:

Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes

i.e. $\mu = 6.3$ minutes

$\sigma=2.2$ minutes

Let x be the long-distance call length.

a. The probability that a call lasts between 5 and 10 minutes will be :-

$P(5$

b. The probability that a call lasts more than 7 minutes. :

$P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z$

c. The probability that a call lasts more than 4 minutes. :

$P(X$

8 0

3 years ago

Let a = {1, 2, 3, 4, 5} b = {1, 3, 5} c = {4, 6}. find the cardinality of the given set. 33. n(a) 34. n(b) 35. n(a ⋃

bearhunter [10]

1) n(a) = 5

The cardinality of a set is the number of elements in that set. So, you simply need to count how many elements belong to the set, and the answer is 5

2) n(b) = 3

Simlarly, in this case you need to count how many elements belong to the set, the answer is 3

3) n(a ⋃ c) = 6

The union of two set is a set composed by all the elements belonging to either one of the sets, with no repetitions. So, since the first set contains all numbers from 1 to 5, the second set contains a 4, which however already belonged to the first set, but also a 6, which is added in the union. So, a ⋃ c = {1,2,3,4,5,6}, and thus n(a ⋃ c)=6.

4) n(a ⋂ c) = 1

The intersection of two sets is a set composed by the elements belonging to both sets. So, 1,2,3 and 5 don't belong to the intersection, because they belong to the first set alone, while 6 doesn't belong to the intersection because they don't belong to the first one. So, a ⋂ c = {4}, and thus n(a ⋃ c)=1.

4 0

4 years ago

Read 2 more answers

a father is 10 times as old as his son. in 5 years he will be 5 times as old as his son. how old is the father and the son now

inn [45]

Answer:

The father is 40 and the son is 4.

Step-by-step explanation:

40 + 5 = 45.

4 +5=9.

45 divided by 5 = 9

5 0

4 years ago