Answer:
the answer is 37.7 so the point closest to 40.
Step-by-step explanation:
A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
Answer:
Parameter
Step-by-step explanation:
Required
Parameter of Statistic
From the question, we understand that the teacher is to calculate the class average.
To calculate the class average, the teacher will use the mean function/formula, which is calculated as:
Generally, mean is an example of a parameter.
<em>So, we can conclude that the teacher will use parameer</em>
(2-a)^2 + 3(2-a)
A^2 -2a + 4 + 6 -3a
A^2 -5a +10
