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insens350 [35]
2 years ago
5

Rewrite f(x) into vertex form by completing the square f(x)=−x2+8x+9​

Mathematics
1 answer:
GalinKa [24]2 years ago
3 0

Answer:

vertex  = ( 4  ,  25 )

Step-by-step explanation:

given a parabola in  standard form  y =  a x 2 + b x + c x ; a ≠ 0

then the x-coordinate of the vertex is

X vertex=-b/2a

y=-x2+8x+9 with a=-1 b=8 c=9

X vertex= -8/-2=4

substitute the value on the equation

Y vertex = -(4)squared+8(4)+9=25

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The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle.
romanna [79]
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate

cot (theta) = -3/5 / y

y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5

Third quadrant => y = -4/5

=> cot (theta) = (-3/5) / (-4/5) = 3/4
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3 years ago
How many times greater is the value of the 2 in 204,936 than the value of the 2 in 124,936
Sliva [168]
I believe it would be C.10
5 0
3 years ago
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Choose one of the factors of 6x^3 + 6
ivanzaharov [21]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

6x^3+6

Now, by factorising , we get

6x^3+6\\=6(x^3+1)

Now, we use the formula i.e.

a^3+b^3=(a+b)(a^2-ab+b^2)

By using this, we get ,

6(x^3+1)\\=6(x+1)(x^2-x+1)

So,

(x+1) \text{ is the factor of }6x^3+6.


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3 years ago
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Which of the following equations has both 1 and −3 as solutions?
soldi70 [24.7K]
The answer is B)

x2+2x−3=0

Factor left side of equation.

(x−1)(x+3)=0

Set factors equal to 0.

x−1=0 or x+3=0

x=1

or

x=−3

5 0
2 years ago
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What is 2(x -3) = 7 (x+24)
amm1812

Answer:

x = -34.8

Step-by-step explanation:

<h2><u>solve the equation</u></h2>

2(x-3)

= 2x - 6

7(x + 24 )

= 7x + 168

put the equation together

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now make x subject of formula:

2x - 7x = 168 +6

-5x = 174

x = 174/ -5

<h3><u>x = -34.8 </u></h3>
3 0
3 years ago
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