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Alik [6]
3 years ago
8

How would the precision of the volume of liquid delivered by the slanted buret be affected?

Chemistry
2 answers:
frosja888 [35]3 years ago
8 0
Hello there.

How would the precision of the volume of liquid delivered by the slanted buret be affected?
by giving you erroneous readings
Olegator [25]3 years ago
6 0
The precision of the <span>volume of liquid delivered by the slanted buret would be affected by giving you erroneous readings. You will have more volume than what really is the volume. Hope this answers the question. Have a nice day.</span>
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v=17200/5.75

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2. d=m/v

v=0.5l

m=425g

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3. use d=m/v again, but not before rewriting the formula for volume: m=vd and  convert dm3 to cm3

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How much CO2 is produced from the combustion of a tank of propane C3H8? Assume the tank contains 9kgs of propane and the molecul
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<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of propane = 9 kg = 9000 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

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The chemical equation for the combustion of propane follows:

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By Stoichiometry of the reaction:

1 mole of propane produces 3 moles of carbon dioxide.

So, 204.08 moles of propane will produce = \frac{3}{1}\times 204.08=612.24mol of carbon dioxide.

Now, calculating the mass of carbon dioxide by using equation 1, we get:

Molar mass of carbon dioxide = 44.01 g/mol

Moles of carbon dioxide = 612.24 moles

Putting values in equation 1, we get:

612.24mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=(612.24mol\times 44.01g/mol)=26944.7g=26.9kg

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