Question

How much CO2 is produced from the combustion of a tank of propane C3H8? Assume the tank contains 9kgs of propane and the molecular weight of propane is 44.1 g/mol
2.7kg 9.0 kg 19.8 kg or 26.9 kg

Answer 1

Answer: The mass of carbon dioxide produced is 26.9 kg

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

Given mass of propane = 9 kg = 9000 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=\frac{9000g}{44.1g/mol}=204.08mol$

The chemical equation for the combustion of propane follows:

$C_3H_8+5O_2\rightarrow 3CO2+4H_2O$

By Stoichiometry of the reaction:

1 mole of propane produces 3 moles of carbon dioxide.

So, 204.08 moles of propane will produce = $\frac{3}{1}\times 204.08=612.24mol$ of carbon dioxide.

Now, calculating the mass of carbon dioxide by using equation 1, we get:

Molar mass of carbon dioxide = 44.01 g/mol

Moles of carbon dioxide = 612.24 moles

Putting values in equation 1, we get:

$612.24mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=(612.24mol\times 44.01g/mol)=26944.7g=26.9kg$

Hence, the mass of carbon dioxide produced is 26.9 kg