Answer:
1083.6 g
Explanation:
At STP, 1 mol of any given mass will occupy 22.4 L.
With the information above in mind we can<u> calculate how many moles of nitrogen gas (N₂) are there in 867 L</u>:
- 867 L ÷ 22.4 L/mol = 38.7 mol
Finally we convert 38.7 moles of N₂ into grams, using its molar mass:
- 38.7 mol * 28 g/mol = 1083.6 g
Answer:
2CaO + 2CO2 → 2CaCO2 + O2 is right
Answer:
90.37 g
Explanation:
From Avogadro Number,
1 mole of every substance contains a particle number of 6.02×10²³
From the question,
1 mole of CH₄ contains 6.02×10²³ molecules.
But,
1 mole of CH₄ has a mass of 16 g
Therefore,
16 g of CH₄ contains 6.02×10²³ molecules
Then,
Y g will contain 3.4×10²⁴ molecules
Solve for Y
Y = (16× 3.4×10²⁴)/(6.02×10²³)
Y = 90.37 g
The answer is b ik it beacuse i did it
Pioneer Species is a community that has reached a stable stage of ecological succession.
