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ddd [48]
3 years ago
13

Please help me, im studying for finals and i need an answer to this question! Will mark brainliest for the best answers!w

Chemistry
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

the generation of electricity and other energy jointly, especially the utilization of the steam left over from electricity generation to produce heat.

I hope it helps!! Have a nice day

Aleks [24]3 years ago
6 0

Answer:

Cogeneration r is the use of a heat engine or power station to generate electricity and useful heat at the same time.

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The molar mass of lif is 25.94 g/mol. how many moles of lif are present in 10.37 g?
zalisa [80]
Number of moles is (actual mass)/(molar mass)
So there are 10.37/25.94 mols
So there are 0.3998 (or 0.4) moles
8 0
3 years ago
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1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

5 0
3 years ago
HELP PLEASE THIS IS MY LAST QUESTION FOR THIS QUIZ
igor_vitrenko [27]

Answer:

Density = 19.3 g/cm³

Explanation:

D = m/v

m = 965 g

v = 50 cm³

so,

965 g / 50 cm³ = 19.3g/cm³

Hope this helps!

6 0
2 years ago
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Which particle changes to create an isotope of an atom? <br> A.proton<br> B.neutron<br> C.electron
Dovator [93]

Answer:

A

Explanation:

proton

5 0
3 years ago
Which scenario is most similar to the type of collision that gas particles have according to kinetic molecular theory?
Ugo [173]
I’m not for sure but I think it’s A.
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