Question

A basket contains six apples and five peaches. Three times, you randomly select a piece of fruit, return it to the basket, and then mix the fruit. All three times, the fruit is an apple. Find the probability of this occuring.

Answer 1

P( it occurring once) =  6/11

Now as the 3  events are independent we multiply the probs:-

P( apple picked 3 times) = 6/11 * 6/11 * 6/11 =  216/1331  or about 16.2%

Answer 2

Answer:

16.22%

Step-by-step explanation:

A basket contains six apples and five peaches.

Total fruits in the basket = 6 + 5 = 11

The probability of selecting a piece of fruit is an apple  $P_{1}=\frac{6}{11}$

Now return it to the basket and select a fruit. so all events are independent.

Therefore, the probability of each time selecting an apple is same.

Probability=$P_{1}\times P_{2}\times P_{3}$

P =$\frac{6}{11}$× $\frac{6}{11}$×$\frac{6}{11}$

  =$\frac{216}{1331}$ = 16.22%

The probability of all three times the fruit is an apple is 16.22%