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kkurt [141]
4 years ago
11

From the top of a vertical cliff 75.0m high, forming one bank of a river, the angles of depression of the top and bottom of a ve

rtical cliff which forms the opposite bank are 22° and 58° respectively. Determine the height of the second cliff and width of the river
Mathematics
1 answer:
Viefleur [7K]4 years ago
4 0

Answer:

a. 46.9 m b. 56.1 m

Step-by-step explanation:

a. Width of the river

The angle of depression of the bottom of the second vertical cliff from the first vertical cliff = angle of elevation of the top of the first vertical cliff from the bottom of the second vertical cliff = 58°.

Since the height of the vertical cliff = 75.0 m, its distance from the other cliff which is the width of the river, d is gotten from

tan58° = 75.0 m/d

d = 75.0/tan58° = 46.87 m ≅ 46.9 m

b. Height of the second cliff

Now, the difference in height of the two cliffs is gotten from

tan22° = h/d, since the angle of depression of the top of second cliff from the first cliff is the angle of elevation of the top of the first cliff from the second cliff = 22°

h = dtan22° = 18.94 m

So, the height of the second cliff is h' = 75.0 - h = 75.0 m - 18.94 m = 56.06 m ≅ 56.1 m

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DedPeter [7]

Answer: 2 solutions.

The given equation breaks down into these two equations

3x+12 = 18 and 3x+12 = -18

Basically 3x+12 equal to plus 18 and minus 18. This is due to the fact that something like |x| = 7 means x = 7 or x = -7, ie those x values are exactly seven units away from zero on the number line.

If you want to solve each equation, then

3x+12 = 18

3x = 18-12

3x = 6

x = 6/3

x = 2 is one solution

and

3x+12 = -18

3x = -18-12

3x = -30

x = -30/3

x = -10 is the other solution

5 0
3 years ago
A ball of radius 17 has a round hole of radius 7 drilled through its center. Find the volume of the resulting solid.
Ahat [919]

Answer:

<h3>19,133.067</h3>

Step-by-step explanation:

Volume of the ball (spherical in nature) Vb = 4/3πrb³

Volume of the hole Vh = 4/3πrh³

rb is the radius of the ball

rh is the radius of the hole

If a ball of radius 17 has a round hole of radius 7 drilled through its center, the volume of the resulting solid will be expressed as:

V = Vb - Vh

V = 4/3πrb³ - 4/3πrh³

factor out the like terms;

V = 4/3π(rb³-rh³)

Given

rb = 17

rh = 7

V = 4/3π(17³-7³)

V = 4/3π(4913-343)

V = 4/3π(4570)

V = (4π*4570)/3

V = 57,399.2/3

V = 19,133.067

Hence the volume of the resulting solid is 19,133.067

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3 years ago
Perform the indicated operation. 10 3/7 + 19 5/9
DanielleElmas [232]
Given expression is

10 \frac{3}{7} + 19 \frac{5}{9}

Now convert mixed fraction as improper fraction as

10 \frac{3}{7} + 19 \frac{5}{9} =  \frac{10*7 + 3}{7} +  \frac{19*9+5}{9}
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                                                         =  \frac{657 + 1232}{63} =  \frac{1889}{63}
Now we can convert \frac{1889}{63 } = 29 \frac{62}{63}

So the answer is 29 \frac{62}63}
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