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3 years ago

14

Need help with this NOW plzzzzz!!!!

1 answer:

Mazyrski [523]3 years ago

3 0

Hello!

The circumference is the diameter multiplied by pi, or the distance around a circle. Since we already have the circumference, and need to find the diameter, we will divide the circumference by pi(3.14).

113.04/3.14=36

The diameter of the circle is 36 units.

I hope this helps!

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A rectangular tank measuring 50 cm x 30 cm x 60 cm was completely filled with water. 1 5 of the water in the tank was transferre

Ierofanga [76]

Answer:

<em>72,000cm³</em>

Step-by-step explanation:

Volume of the rectangular tank = Length * Width * Height

Given

Length = 50cm

Width = 30cm

Height = 60cm

Get the volume:

Volume = 50*30*60

Volume = 90,000cm³

Hence the volume of the rectangular tank is 90,000cm³.

If 1/5 of the volume of water was transferred to another tank, the volume transferred will be:

Amount transferred = 1/5 * 90,000

Amount transferred = 18000cm³

Amount left in the tank = 90,000 - 18,000

<em>Amount of water left in the tank = 72,000cm³</em>

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2 years ago

How to simplify (-12)-7×(-12)7

Strike441 [17]

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3 years ago

Theorem: A line parallel to one side of a triangle divides the other two proportionately.

Elenna [48]

Answer:

Segment BF = 16 is true.

Step-by-step explanation:

Since, DE is parallel to BC, so DE will divide AB and AC proportionally.

Hence,

$\frac{AE}{EC} = \frac{AD}{DB}$

⇒ $\frac{12}{18} = \frac{6}{DB}$

{Since, given that AE = 12, EC = 18 and AD = 6}

⇒ BD = 9.

Again, since, EF is parallel to AB, so EF will divide BC and AC proportionally.

Hence, $\frac{CE}{AE} = \frac{FC}{BF}$

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3 years ago

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Step-by-step explanation:

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3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago