Answer:
D. (1/4, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -8x
4x - y = 3
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 4x - (-8x) = 3
- Simplify: 4x + 8x = 3
- Combine like terms: 12x = 3
- Isolate <em>x</em>: x = 3/12
- Simplify: x = 1/4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -8x
- Substitute in <em>x</em>: y = -8(1/4)
- Multiply: y = -2
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)
The above three expressions could be used to represent the numbers.
Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44
x = 11, y = 7, z = 44.
Answer:
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