3 years ago

Mark drove 50 percent of the distance.

Mathematics

1 answer:

Lapatulllka [165]3 years ago

6 0

Break everything into 8ths.

50% = 1/2=4/8

4/8+1/8=5/8
the remaining distance is 8/8-5/8. so 3/8, not 1/4

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The width of a rectangle is 6 2/3 inches. The length of the is twice it’s width. What so the perimeter of the rectangle?

Nookie1986 [14]

$\text {Width = } 6\dfrac{2}{3} \text { inches}
$

The length is twice its width:
$\text {Length = } 2 \times 6\dfrac{2}{3} \text { inches}$

Change to improper fraction:
$\text {Length = }2 \times \dfrac{20}{3} \text { inches}$

Combine into single fraction:
$\text {Length = } \dfrac{40}{3} \text { inches}$

Find Perimeter :
$\text {Perimeter = Length + Length + Width + Width}$

$\text {Perimeter = } \dfrac{40}{3} + \dfrac{40}{3} + \dfrac{20}{3} + \dfrac{20}{3} = \dfrac{120}{3} = 40 \text { inches}$

$\bf \text {Answer: Perimeter = 40 inches}$

6 0

3 years ago

Read 2 more answers

Answer this correct and I will give you extra points.

IRINA_888 [86]

Answer:

he didnt subtract each equations on both sides

5y-6=4y+1

-4 -4

y -6=1

+6=+6

y=7