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Ilya [14]
2 years ago
11

100 pts/ x3+y3+z3=k

Mathematics
1 answer:
lesya692 [45]2 years ago
3 0

Answer:

.............................

Step-by-step explanation:

..........................

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This monitor has a diagonal length of 19 inches and an aspect ratio of 5:4. What are the width and height of the monitor? Round
nasty-shy [4]

<em>Rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>

<h2>Explanation:</h2><h2 />

The aspect ratio is defined as:

<em>"The proportional relationship between the width and height of an image"</em>

It is usually expressed in a mathematical language as:

x:y \\ \\ x: \ Width \\ \\ y: \ Height

So, it is true that:

x:y=5:4 \\ \\ or: \\ \\ \frac{x}{y}=\frac{5}{4} \\ \\ \therefore x=\frac{5y}{4}

In this case, we know that the monitor has a diagonal length (D):

D=19in

So, by Pythagorean theorem:

D^2=361 \\ \\ 361=x^2+y^2 \\ \\ Since \ x=\frac{5y}{4}

D^2=361 \\ \\ 361=x^2+y^2 \\ \\ Since \ x=\frac{5y}{4} \\ \\ 361=\left(\frac{5y}{4}\right)^2+y^2 \\ \\ 361=\frac{25y^2}{16}+y^2 \\ \\ \frac{41}{16}y^2=361 \\ \\ y^2=\frac{261\times 16}{41} \\ \\ y=\sqrt{140.87} \\ \\ y=11.869in

Finding x:

x=\frac{5(11.869)}{4} \\ \\ x=14.836in

<em>Finally, rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>

<h2>Learn more:</h2>

Pythagorean Theorem: brainly.com/question/10182890

#LearnWithBrainly

5 0
3 years ago
3 \frac{1}{4}[/tex] = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D" id="TexFormula1" title="\frac{1}{2}" alt="\frac{1
adelina 88 [10]

Answer:

Look below

Step-by-step explanation:

Conversion a mixed number 3 1/

4

to a improper fraction: 3 1/4 = 3 1/

4

= 3 · 4 + 1/

4

= 12 + 1/

4

= 13/

4

To find new numerator:

a) Multiply the whole number 3 by the denominator 4. Whole number 3 equally 3 * 4/

4

= 12/

4

b) Add the answer from previous step 12 to the numerator 1. New numerator is 12 + 1 = 13

c) Write a previous answer (new numerator 13) over the denominator 4.

Three and one quarter is thirteen quarters

Conversion a mixed number 2 1/

3

to a improper fraction: 2 1/3 = 2 1/

3

= 2 · 3 + 1/

3

= 6 + 1/

3

= 7/

3

To find new numerator:

a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2 * 3/

3

= 6/

3

b) Add the answer from previous step 6 to the numerator 1. New numerator is 6 + 1 = 7

c) Write a previous answer (new numerator 7) over the denominator 3.

Two and one third is seven thirds

Add: 13/

4

+ 7/

3

= 13 · 3/

4 · 3

+ 7 · 4/

3 · 4

= 39/

12

+ 28/

12

= 39 + 28/

12

= 67/

12

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(4, 3) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 4 × 3 = 12. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - thirteen quarters plus seven thirds = sixty-seven twelfths.

3 0
2 years ago
Whats the sum of p 3/4
Gnoma [55]
The sum oh p 3/4 should be 3.333
6 0
3 years ago
An architect drew plans for an office building.
Sav [38]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
Which of the following shows the length of the third side, in inches, of the triangle below? (1 point)
GrogVix [38]

Answer:

2, sqrt of 7633

Step-by-step explanation:

for now, we'll leave the 3rd side as x

y using the Pythagorean theorem, we can conclude that (1) 48^2+x^2=73^2 or (2) 48^2+73^2=x^2.

1. If we conclude the x isn't the longest, the x would be 3025 which is the sqrt of 55, now is invalid because the 2 smallest sides can't be more than the longest side when they add up 55+48>73 so that is invalid

2. Then, it leaves us with only 1 choice left! concluding that the 3rd side is the longest. Which the answer is sqrt of 7633

6 0
2 years ago
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