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fomenos
3 years ago
8

Geometry: CC 2015 > Chapter 2: Chapter 2 Test >

Mathematics
1 answer:
tankabanditka [31]3 years ago
7 0

Answer:

The area of ABCF is 2 and 2 × AB = 4

The statement proves that the conjecture is false

Step-by-step explanation:

A conjecture is a proposition or conclusion that is presumed to be true or correct but which is based on incomplete details or information

Given the length of the sides of rectangle ABDE, we have;

Length AB = 2 units

Length DE = 2 units

The area of ABDE = 2 × 2 = 4 unit²

Therefore, the area of the rectangle ABDE is equal to 2 × the length of either AB or DE

However, the are of rectangle ABCF = 2 × 1 = 2 unit²

While the area of rectangle 2 × the length of side AB = 2 × 2 = 4 unit², which is not equal to the number of square units in the area of the rectangle.

Therefore;

The area of ABCF is 2 and 2 × AB = 4

The statement (above) proves that the conjecture is false.

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Answer:

There is an 84% probability that your standard refrigerator will last between 12 and 20 years.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A standard refrigerator's mean life expectancy is 18 years with a standard deviation of 2 years. This means that \mu = 18, \sigma = 2.

What is the probability that your standard refrigerator will last between 12 and 20 years?

This probability is the pvalue of Z when X = 20 subtracted by the pvalue of Z when X = 12. So

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 18}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{12- 18}{2}

Z = -3

Z = -3 has a pvalue of 0.0014

This means that there is a 0.8413-0.0014 = 0.8399 = 0.84 = 84% probability that your standard refrigerator will last between 12 and 20 years.

5 0
3 years ago
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