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shutvik [7]
3 years ago
14

15-8x Choose ALL of the statements that are TRUE. The factors are 8 and x. The coefficient is -8. The constant is -8. The terms

are 15 and -8x. The coefficient is 15. The constant is 15.
Mathematics
2 answers:
Aneli [31]3 years ago
8 0

Answer:

3 Answers:

Coefficient is -8

Terms are 15 and -8x

Constant is 15

Explanation:

The coefficient is the number just to the left of the variable. So that's why -8 is the coefficient for -8x. This is the variable term while 15 is the constant (it has no variable multiplied with it). The two terms are 15 and -8x since we can write 15-8x as 15+(-8x). Terms are separated by a plus sign.

Step-by-step explanation:

baherus [9]3 years ago
5 0
<h3>3 Answers:</h3>
  • Coefficient is -8
  • Terms are 15 and -8x
  • Constant is 15

Explanation:

The coefficient is the number just to the left of the variable. So that's why -8 is the coefficient for -8x. This is the variable term while 15 is the constant (it has no variable multiplied with it). The two terms are 15 and -8x since we can write 15-8x as 15+(-8x). Terms are separated by a plus sign.

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A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

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             s = sample standard deviation = 6.72 minutes

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             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

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P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

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Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

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