Graph of f(x-3) is compressed by a factor of
horizontally of f(x).
<u>Step-by-step explanation:</u>
We have, the graph of f(x)=
, on replacing f(x) by f(x-3) we get:
=
.Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of
horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph :
.
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
Answer: the answer is A.4
Step-by-step explanation:
Dilation in this context is the transformation is an object into a larger one.
ABC is transformed to A'B'C'
To get the scale factor, we divide the coordinates of A'B'C' by ABC
i.e
A'/A = -28/-7, 32/8 = 4
Or
B'/B = 4/1, -28/-7 = 4
Or
C'/C = 28/7, 24/6 = 4
The lcd would be 10x^3y^3