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konstantin123 [22]
4 years ago
11

If two locations are 1 km apart in actuality but only 1 cm apart on a map, what is the map's scale? A. 1:1,000 B. 1:10,000 C. 1:

100,000 D. 1:1,000,000
Mathematics
2 answers:
Nimfa-mama [501]4 years ago
6 0

Answer:

C

Step-by-step explanation:

1 km = 100,000 cm

kogti [31]4 years ago
5 0

Answer:

1:100,000

Step-by-step explanation:

One km is 1000 times a meter and 100,000 times a cm.

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rosijanka [135]
-8x+7-6(x-1)=-6x-(7x-5)+6
-8x+7-6x+6=-6x-7x+5+6
use gemdas to add like terms
-14x+13=-13x+11
+14x. +14x
13= x+11
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6 0
4 years ago
In parallelogram ABCD, points E and F are the midpoints of side AB and BC, respectively. A F meets DE at G and BD at H. What is
patriot [66]

Answer:

The area of the quadrilateral B-H-G-E is 7

Step-by-step explanation:

The area of the parallelogram = 60  

It can be shown that ΔG-D-F = 3/10 × Area of the parallelogram S = 3/10×S

Because the diagonal B-D shares A-F into the ratio 1:2, the ΔH-D-A = 2/3×ΔD-B_A  where ΔD-B_A = 1/2·S, therefore, ΔD-B_A = 2/3×1/2×S = 1/3×S

ΔB-F-H is similar to ΔD-B_A scaled to 1/2,

Therefore;

The area of ΔB-F-H = 1/4×Area of ΔD-B_A = 1/4×1/3×S = 1/12×S,

ΔF-C-D = 1/4×S

ΔE-A-D = 1/4×S

The area of the quadrilateral B_H_G_E found as follows;

Area B_H_G_E  = S - (ΔF-C-D + ΔG-D-F +ΔE-A-D +ΔB-F-H)

Area B_H_G_E  = S - (1/4×S + 1/10×S +1/4×S +1/12×S) = S - 53/60×S = 7/60×S

Whereby we are given that the area, S of the parallelogram AB-CD = 60 we have;

Area B_H G_E  = 7/60×60 = 7

8 0
4 years ago
Help please ..........
Bumek [7]
Graph B should be correct
5 0
4 years ago
2/5 of 16= (estimate each product)
ahrayia [7]

Answer:

6.4 rounds down to 6.

Step-by-step explanation:

Divide 16 by 5. Multiply that number by 2.

3 0
3 years ago
Read 2 more answers
837,164 and 4,508 the value of 8
eimsori [14]
In 837,164, the value of 8 is the hundred thousands place
In 4,508, the value of 8 is the ones place

hope this helps
7 0
3 years ago
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