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konstantin123 [22]

3 years ago

11

If two locations are 1 km apart in actuality but only 1 cm apart on a map, what is the map's scale? A. 1:1,000 B. 1:10,000 C. 1:

100,000 D. 1:1,000,000

2 answers:

Nimfa-mama [501]3 years ago

6 0

Answer:

C

Step-by-step explanation:

1 km = 100,000 cm

kogti [31]3 years ago

5 0

Answer:

1:100,000

Step-by-step explanation:

One km is 1000 times a meter and 100,000 times a cm.

You might be interested in

For bone density scores that are normally distributed with a mean of 0 and a standard deviation of 1, find the percentage of sc

gogolik [260]

Answer:

a) The percentage of bone density scores that are significantly high is 2.28%

b) The percentage of bone density scores that are significantly low is 2.28%

c) The percentage of bone density scores that are not significant is 95.44%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. significantly high (or at least 2 standard deviations above the mean).

This is 1 subtracted by the pvalue of Z = 2.

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of scores are signifcantly high

b. significantly low (or at least 2 standard deviations below the mean).

pvalue of Z = -2

Z = -2 has a pvalue of 0.0228

2.28% of scores are signicantly low.

c. not significant (or less than 2 standard deviations away from the mean).

pvalue of Z = 2 subtracted by the pvalue of Z = -2.

Z = 2 has a pvalue of 0.9772

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% of the scores are not significant

7 0

3 years ago

PLEASE HELP!!!!<br> I need to solve for a, b, and c

nirvana33 [79]

Answer:

25000 seats in section A
14100 seats in sectin B
10900 seats in section C

Step-by-step explanation:

The problem statement tells you half the total number of seats are in section A, so you already know that there are 25000 A seats. The revenue from those seats is

... 25000×$25 = $625,000

so the revenue from B and C seats must total

... $1,070,500 - 625,000 = $445,500

If all 25000 of the B/C seats were C seats, the revenue would be

... 25000×$15 = $375,000

The actual revenue from those seats is $445,500 -375,000 = $70,500 more than that. We know each B seat generates $5 more revenue, so there must be ...

... $70,500/$5 = 14,100 . . . . B seats

Then the balance of the 25000 B and C seats are C seats:

... 25,000 - 14,100 = 10,900 . . . . C seats

_____

<em>Alternate Solution Method</em>

The new Brainly answer format requires the answer be supplied before the working. In order to find the answer quickly so that I can fill in that section, I used a matrix method for solving the problem. The problem equations can be written ...

a + b + c = 50000
a - b - c = 0
25a + 20b + 15c = 1070500

so the augmented matrix is ...

$\left[\begin{array}{cccc}1&1&1&50000\\1&-1&-1&0\\25&20&15&1070500\end{array}\right]$

A graphing calculator can be used to find the solution to this, generally using a function that produces the reduced row-echelon form. The attachment shows the solution using a TI-84 calculator.

___

<em>Comment on the Working</em>

Since the number of A seats is equal to the total of B and C seats, the number of A seats must be half the total number of stadium seats. Having figured that out, the problem is reduced to one of finding the mix of B and C seats that will produce the remaining revenue.

As with many mixture problems, it is convenient to look at differences. Start with the assumption that all of the desired revenue comes from the least contributor. Here, that is C seats. Then figure the difference that using a B seat makes ($20 -15 = $5) and the difference of the actual revenue and the amount that you got by assuming all C seats: 445,500 -375,000 = 70,500. Since replacing a C seat by a B seat adds $5 to the revenue, it is easy to figure the number of such replacements required in order to raise the revenue by $70,500.

If you write the equation for B seats, you find the solution to the equation mirrors this verbal description:

... 20b + 15(25000-b) = 445,500

... 5b = 445,500 - 375000 . . . . simplify, subtract 375000

... b = 70500/5 = 14100

8 0

3 years ago

$1000 is invested at 2.9% annual interest for 6 months.<br> a. Simple Interest b. Compound Interest

kirza4 [7]

Answer:

a. Simple interest = $174

b. Compund interest = $1187.1

Step-by-step explanation:

Given the following data;

Principal, P = $1000

Interest, R = 2.9%

Time, T = 6 months

a. To find the simple interest;

S.I = (PRT)/100

S.I = (1000*2.9*6)/100

S.I = 17400/100

S.I = $174

b. To find the compound interest;

$A = P(1 + \frac{r}{100})^{t}$

Substituting into the formula, we have;

$A = 1000(1 + \frac{2.9}{100})^{6}$

$A = 1000(1 + 0.029)^{6}$

$A = 1000(1.029)^{6}$

$A = 1000(1.1871)$

A = $1187.1

8 0

3 years ago

(6,-3) and y = - 6x - 3

Hatshy [7]

Wait what's the question tho?
is it if this point is on the line?
cause it's not
-y=mx+b
3=-6(6)-3
-3=-36-3
-3 does not equal -39
hence, point is not on the line

3 0

3 years ago

Terrance and his family are planning how to pay for his college education. The cost of tuition at his chosen college is $14,500

Finger [1]

Answer:

terrence will have to play 2900

Step-by-step explanation:

80% * 14500

14500-11600

2900

6 0

3 years ago