.In a _____ relationship one variable increases and a second variable increases proportionally,

How many grams of H3PO4 are in 175mL of a 2.50M solution of H3PO4?

solmaris [256]

<span>(0.1875 moles)(98.004 g/mole) = 18.37575 g </span>
<span>In correct number of significant figures: 18.4 </span>

5 0

3 years ago

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The orbital radius of Venus is 0.72 AU. What is this distance in kilometers? (One AU is about 150 million kilometers.)

Evgen [1.6K]

<span>The answer is D) 108 million kilometers. To solve this problem, you must perform a simple unit conversion calculation. 1 AU = 150,000,000 km is the conversion factor. Take the radius of Venus, .72 AU, and multiply it by 150,000,000 km/1 AU. You flip the conversion factor so that the units of the original distance in the numerator cancel the units in the denominator of the conversion factor. completing the calculation gives you 108,000,000 km</span>

6 0

3 years ago

What would happen if a neutron was added to Lithium (7)

Ainat [17]

Answer:

if you add a neutron to lithium-7 it becomes a compound nucleus of lithium-8

8 0

3 years ago

calculate the speed of an electron if its de broglie wavelength is twice its displacement in one second

valkas [14]

Answer:

The speed of an electron is 0.01908 m/s.

Explanation:

De-Broglie wavelength is given by:

$\lambda=\frac{h}{mv}$

where, $\lambda$ = wavelength of a particle

h = Planck's constant = $6.626\times 10^{-34}Js$

m = mass of particle

v = velocity of the particle

Velocity of an electron = v

Mass of an electron = $9.1\times 10^{-31}kg$

Wavelength of electron is twice the displacement in seconds which is velocity of an electron.

Then.wavelength of an electron = $\lambda =2v$

$\lambda =2v=\frac{6.626\times 10^{-34}Js}{9.1\times 10^{-31}kg\times v}$

v = 0.01908 m/s

The speed of an electron is 0.01908 m/s.

5 0

3 years ago

Which formula is an empirical formula?

poizon [28]

<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. $NH_{3}$

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

$MolecularFormula=n(EmpiricalFormula)$

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. $N_{2}O_{4}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$N_{2}O_{4}=2(NO_{2})$

B. $NH_{3}$

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. $C_{3}H_{6}$