Answer:
Calcium for 2+ charge and Fluorine forms 1- charge
Explanation:
Answer:
The reduced atom is Br.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>2Na + Br₂ → 2NaBr,
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Na loses 1 electrons and is oxidized to Na⁺. (Na → Na⁺ + e).
Br₂ gains 2 electrons and is reduced to 2Br⁻. (Br₂ + 2e → 2Br⁻).
<em>So, the reduced atom is Br.</em>
The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.
BALANCING EQUATION:
- Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.
- According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl
- Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:
4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl
Learn more at: brainly.com/question/21049751?referrer=searchResults
Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals.
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