three numbers have a sum of 100. the difference between the two larger numbers is 12. the difference between the two smaller num
bers is 2. what are the three numbers
2 answers:
Answer:
28 + 30 + 42 = 100
Step-by-step explanation:
s=small number
s+ (s+2) + (s+2 +12) =100
3s +16 = 100
3s =84
s = 28
small 28
mediam 28+2 = 30
large 30+12 = 42
<h2>
Answer:</h2>
- The largest number is: 42
- and the smallest number is: 28
<h2>
Step-by-step explanation:</h2>
Let the largest number be x.
Let the middle number be y
and let the smallest number be z.
Now, it is given that:
Three numbers have a sum of 100.
This means that:
x+y+z=100-------(1)
Also,
The difference between the two larger numbers is 12.
i.e.
x-y=12
i.e.
x=12+y----------(2)
Also
The difference between the two smaller numbers is 2.
i.e.
y-z=2
i.e.
z=y-2---------(3)
On putting the value of x and z from equation (2) and equation (3) into equation (1) we have:
12+y+y+y-2=100
i.e.
10+3y=100
i.e.
3y=100-10
i.e.
3y=90
i.e.
y=90/3
i.e.
y=30
Hence, x=30+12
i.e. x=42
and
z=30-2
i.e.
z=28
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