Answer:
28 + 30 + 42 = 100
Step-by-step explanation:
s=small number
s+ (s+2) + (s+2 +12) =100
3s +16 = 100
3s =84
s = 28
small 28
mediam 28+2 = 30
large 30+12 = 42
Let the largest number be x.
Let the middle number be y
and let the smallest number be z.
Now, it is given that:
Three numbers have a sum of 100.
This means that:
x+y+z=100-------(1)
Also,
The difference between the two larger numbers is 12.
i.e.
x-y=12
x=12+y----------(2)
Also
The difference between the two smaller numbers is 2.
y-z=2
z=y-2---------(3)
On putting the value of x and z from equation (2) and equation (3) into equation (1) we have:
12+y+y+y-2=100
10+3y=100
3y=100-10
3y=90
y=90/3
y=30
Hence, x=30+12
i.e. x=42
and
z=30-2
z=28
the solution is b
(-2,8) (0,4) (2,8)
Answer: 1,208 seats
39-18= 21
18 x 478 = 8,604
21 x 292 = 6,132
8,604 + 6,132 = 14,736
14,736 - 13,528 = 1,208
1/3 is bigger than 30%
15/2
My interpretation of your math expression is "2 1/2 divided by 1/3."
I prefer to write this as:
5 1
----- ÷ -----
2 3
which is equivalent to:
5 3
----- * ----- = 15/2
2 1