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Kipish [7]
2 years ago
14

Simplify the algebraic experssion 8x+16y /2 +4 (x-y)

Mathematics
2 answers:
MissTica2 years ago
7 0
\frac{8x + 16y}{2+4(x-y)}
\frac{4(2x + 16y)}{4(0.5+x-y)}
\frac{2x+16y}{0.5+x-y}
This is the furthest I have got. Sorry, but this answer may not be complete
erica [24]2 years ago
6 0
8x+64xy-224y this is the answer
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Write down the value of 2 with the power of 3
beks73 [17]

Answer:8

Step-by-step explanation:2 x 2=4 x 2=8

6 0
3 years ago
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600000×2+100000-60=____
dsp73

Answer:

1299940 i think

Step-by-step explanation:

Please mark as Brainliest! :)

Have a nice day.

8 0
3 years ago
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What is a equivalent fraction of 10/25, 6/8, 3/5, 1/10​
user100 [1]

Answer:

Step-by-step explanation:

10/25=20/50=40/100

6/8=3/4=12/16

3/5=6/10=60/100

1/10=10/100

6 0
3 years ago
Can anyone help me out on this question?
svp [43]

Firstly , we will check continuity at x=1

we can use method

Suppose, f(x) is continuous at x=c

then it must satisfy

\lim_{x \to c} f(x)=f(c)

\lim_{x \to 1} f(x)=f(1)

firstly , we can find limit

\lim_{x \to 1-} f(x)=  \lim_{x \to 1-}(x+3)=1+3=4

\lim_{x \to 1+} f(x)=  \lim_{x \to 1-}(3x+1)=3*1+1=4

so, we get

\lim_{x \to 1} f(x)= 4

now, we can find f(1)

f(1)=3*1+1=4

so, we got

\lim_{x \to 1} f(x)=f(1) =4

so, this is continuous at x=1

Hence , option-D...........................Answer

5 0
3 years ago
Which statements about the function are true? Select two
iogann1982 [59]

Answer:

The vertex of the function is at (1,-25)

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

<em>Part of the graph of the function f(x) = (x + 4)(x-6) is shown  below. </em>

<em>Which statements about the function are true? Select two </em>

<em>options. </em>

<em>The vertex of the function is at (1,-25). </em>

<em>The vertex of the function is at (1,-24). </em>

<em>The graph is increasing only on the interval -4< x < 6. </em>

<em>The graph is positive only on one interval, where x <-4. </em>

<em>The graph is negative on the entire interval  </em>

My answer:

Given the factored form of the function:

f(x) = (x + 4)(x-6)

<=> f(x) = x^{2} - 2x -24

We will convert to vertex form

<=> f(x) = (x^{2} - 2x +1) - 25

<=> f(x) = (x-1)^{2} -25

=> the vertex of the function is: (1,-25)

We choose: a. The vertex of the function is at (1,-25)

Let analyse other possible answers:

<u>c. The graph is increasing only on the interval -4< x < 6.</u>

Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.

So the graph is increasing in the domain (1, +∞)

=> C is wrong

<u>d. The graph is positive only on one interval, where x <-4</u>

Wrong, The graph is positive only on one interval, where x > 6

<u>e. The graph is negative on the entire interval</u>

Wrong, The graph is negative only on one interval, where -4< x < 6.

7 0
3 years ago
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