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Westkost [7]
3 years ago
14

5(4n - 11) - 3n + 20 and 17n - 35 are equivalent expressions.(true or false)please exlplain with FULL SENTANCES

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0
Yo has to distribute and add like terms
distributeiv propoerty
a(b+c)=ab+ac aka
a(b-c)=ab-ac

5(4n-11)-3n+20=17n-35
distribuet
5*4n=20n
5*11=55
20n-55-3n+20=17n-35
move like terms together
20n-3n+20-55=17n-35
20-3=17
20-55=35
17n-35=17n-35
true
kari74 [83]3 years ago
3 0
True. Because 5(4n-11)-3n+20 is 20n-55-3n+20 and when you add like terms together you get 17n-35 as your answer which is the same as 17n-35.
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Read 2 more answers
Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?
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Answer:

-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-\frac{1}{3}i + \frac{5}{2}j)

-1.2i - 1.6j + 0.6i - 1.5j - \frac{0.2}{3}i + 0.5j

Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

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\frac{-18i + 9i - i}{15} = -\frac{2}{3}i

<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

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