All categories

3 years ago

Find the equation in the line shown please Is for today

Mathematics

1 answer:

Olegator [25]3 years ago

3 0

Step-by-step explanation:

i hope i have been useful buddy.

good luck ♥️♥️♥️♥️♥️.

You might be interested in

Which expression shows how to correctly determine the speed in meters per second?

inn [45]

Answer:

B.?

Step-by-step explanation:

i just took the test and i think B.18 seconds ÷ 402 meters

is the right answer plz tell lily~chan if shes wrong!

3 0

3 years ago

You are checking a bag at the airport. Your bag weighs 16 pounds plus 2 more pounds for each souvenir you add. How many souvenir

Nana76 [90]

Answer:

Step-by-step explanation:

50 - 16 = 34

34 / 2 = 17

34 + 17 = 51, which is too much; so we take 1 souvenir out which would be 16.

Quick check:

34 + 16 = 50

Hope this helps!

7 0

2 years ago

Simplify the expression. 3\5x + 19 - 3/20x -7

MatroZZZ [7]

Answer:

9/20 x+12

Step-by-step explanation:

4 0

3 years ago

Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. The ticket cost $4. Which system of linear equations

Anvisha [2.4K]

Answer:

n + q = 28 0.05n + 0.25q = 4

3 0

3 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago