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insens350 [35]
3 years ago
12

Find the equation in the line shown please Is for today

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Step-by-step explanation:

i hope i have been useful buddy.

good luck ♥️♥️♥️♥️♥️.

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Which expression shows how to correctly determine the speed in meters per second?
inn [45]

Answer:

B.?

Step-by-step explanation:

i just took the test and i think B.18 seconds ÷ 402 meters

is the right answer plz tell lily~chan if shes wrong!

3 0
3 years ago
You are checking a bag at the airport. Your bag weighs 16 pounds plus 2 more pounds for each souvenir you add. How many souvenir
Nana76 [90]

Answer:

16

Step-by-step explanation:

50 - 16 = 34

34 / 2 = 17

34 + 17 = 51, which is too much; so we take 1 souvenir out which would be 16.

Quick check:

34 + 16 = 50

Hope this helps!

7 0
2 years ago
Simplify the expression.<br> 3\5x + 19 - 3/20x -7
MatroZZZ [7]

Answer:

9/20 x+12

Step-by-step explanation:

4 0
3 years ago
Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. The ticket cost $4. Which system of linear equations
Anvisha [2.4K]

Answer:

n + q = 28 0.05n + 0.25q = 4

3 0
3 years ago
Read 2 more answers
Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
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