The answer would be [B] 636.48 ft2
Answer:
3.5 divided by 100
Step-by-step explanation:
So we know that one millimeter is equal to 0.01
To solve the equation you would multiply 3.5 x .01 = .035
Another way would be if you divide 3.5/100 = .035
Hope that helps and have a great day!
Answer:
C or D
Step-by-step explanation:
Answer:
Plot attached
Step-by-step explanation:
We want to locate √36 and ∛36 on the given number line
Now, √36 = 6.
And ∛36 = 3.3
I have attached a plot number line both values as we are told in the question
Answer:
The probability that a person has HIV given that the test negative is 0.0033.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = a person in Uganda had HIV
<em>Y</em> = a person in Uganda was tested positive for HIV.
The information provided is:
![P(Y^{c}\cap X)=\frac{4}{1517}\\](https://tex.z-dn.net/?f=P%28Y%5E%7Bc%7D%5Ccap%20X%29%3D%5Cfrac%7B4%7D%7B1517%7D%5C%5C)
![P(Y\cap X)=\frac{166}{1517}\\](https://tex.z-dn.net/?f=P%28Y%5Ccap%20X%29%3D%5Cfrac%7B166%7D%7B1517%7D%5C%5C)
![P(Y\cap X^{c})=\frac{129}{1517}\\](https://tex.z-dn.net/?f=P%28Y%5Ccap%20X%5E%7Bc%7D%29%3D%5Cfrac%7B129%7D%7B1517%7D%5C%5C)
![P(Y^{c}\cap X^{c})=\frac{1218}{1517}\\](https://tex.z-dn.net/?f=P%28Y%5E%7Bc%7D%5Ccap%20X%5E%7Bc%7D%29%3D%5Cfrac%7B1218%7D%7B1517%7D%5C%5C)
The probability that a person has HIV given that he/she was tested negative is:
![P(X|Y^{c})=\frac{P(Y^{c}\cap X)}{P(Y^{c})}](https://tex.z-dn.net/?f=P%28X%7CY%5E%7Bc%7D%29%3D%5Cfrac%7BP%28Y%5E%7Bc%7D%5Ccap%20X%29%7D%7BP%28Y%5E%7Bc%7D%29%7D)
Compute the probability of a person not having HIV as follows:
![P(Y^{c})=P(Y^{c}\cap X)+P(Y^{c}\cap X^{c})=\frac{4}{1517}+\frac{1218}{1517} =\frac{4+1218}{1517} =\frac{1222}{1517}](https://tex.z-dn.net/?f=P%28Y%5E%7Bc%7D%29%3DP%28Y%5E%7Bc%7D%5Ccap%20X%29%2BP%28Y%5E%7Bc%7D%5Ccap%20X%5E%7Bc%7D%29%3D%5Cfrac%7B4%7D%7B1517%7D%2B%5Cfrac%7B1218%7D%7B1517%7D%20%20%3D%5Cfrac%7B4%2B1218%7D%7B1517%7D%20%3D%5Cfrac%7B1222%7D%7B1517%7D)
Compute the value of
as follows:
![P(X|Y^{c})=\frac{P(Y^{c}\cap X)}{P(Y^{c})}=\frac{4}{1517}\times\frac{1517}{1222}=0.0033](https://tex.z-dn.net/?f=P%28X%7CY%5E%7Bc%7D%29%3D%5Cfrac%7BP%28Y%5E%7Bc%7D%5Ccap%20X%29%7D%7BP%28Y%5E%7Bc%7D%29%7D%3D%5Cfrac%7B4%7D%7B1517%7D%5Ctimes%5Cfrac%7B1517%7D%7B1222%7D%3D0.0033)
Thus, the probability that a person has HIV given that he/she was tested negative is 0.0033.