Answer:
see explanation
Step-by-step explanation:
using the trigonometric identities
• sin2x = 2sinxcosx
• cos2x = 2cos²x - 1
• sin²x + cos²x = 1
sinx = ± 
= ± 
= ± 
= ± 
= ± 
since sinΘ > 0 then sinΘ = = 
sin2Θ = 2 × × - 
= - 
cos2Θ = 2 × (- )² - 1
= 2 × 
- 1
= 
- 1 = 
= 
Can you please show us the problems
Starting with 5^0 (since in PEMDAS, we have parenthesis, exponents, multiplication, division, addition, and subtraction, and exponents come before multiplication), we know that anything to the power of 0 equals 1. Therefore, 5^0=1. Next, for 2^1, anything to the power of 1 means it's that number, so 2^1=2. Note that for 2^3 (and for most exponents), however, it's 2 multiplied by itself 3 times, or 2*2*2=8. Since 5^0=1 and 2^1=2, 5^0*2^1=1*2=2
Feel free to ask with further questions!
