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alexandr1967 [171]
4 years ago
14

When helping someone whose car has a "dead" battery, how should your car's battery be connected in relation to the dead battery?

Physics
1 answer:
leonid [27]4 years ago
8 0
Positive terminal with Positive terminal. The negative terminal should be connected to the car chassis.
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A potential difference of 3.27 nV is set up across a 2.16 cm length of copper wire that has a radius of 2.33 mm. How much charge
miskamm [114]

Answer:

Charge = 4.9096 x 10⁻⁷ C

Explanation:

First, we find the resistance of the copper wire.

R = ρL/A

where,

R = resistance = ?

ρ = resistivity of copper = 1.69 x 10⁻⁸ Ω.m

L = Length of wire = 2.16 cm = 0.0216 m

A = Cross-sectional area of wire = πr² = π(0.00233 m)² = 1.7 x 10⁻⁵ m²

Therefore,

R = (1.69 x 10⁻⁸ Ω.m)(0.0216 m)/(1.7 x 10⁻⁵ m²)

R = 2.14 x 10⁻⁵ Ω

Now, we find the current from Ohm's Law:

V =IR

I = V/R

I = 3.27 x 10⁻⁹ V/2.14 x 10⁻⁵ Ω

I = 1.52 x 10⁻⁴ A

Now, for the charge:

I = Charge/Time

Charge = (I)(Time)

Charge = (1.52 x 10⁻⁴ A)(3.23 x 10⁻³ s)

<u>Charge = 4.9096 x 10⁻⁷ C</u>

8 0
4 years ago
3. The atmospheres of Mars and Venus are mostly carbon dioxide. Earth'satmosphere contains only a fraction of a percent of carbo
maria [59]

Answer:

Earth's atmosphere is a mixture of nitrogen (79%), oxygen (20%), and a small fraction of carbon dioxide, water vapours and other gases. However, the atmospheres on Venus and Mars mainly consist of carbon dioxide.

Explanation:

3 0
3 years ago
The coefficent of static friction between the floor of a truck and a box resting on it is 0.38. The truck is traveling at 87.9 k
nekit [7.7K]

Answer:

d=79.9m

Explanation:

From the question we are told that:

coefficient of static friction \mu=0.38

Velocity v=87.9=>24.41667m/s

Generally the equation for Conservation of energy is mathematically given by

 \mu*mgd = 0.5 m v^2

 d=\frac{0.5*24.42^2}{0.38*9.8}

 d=79.9m

3 0
3 years ago
The diagram shows a proposed design for a ship that could be used for long-distance space travel. Explain why the ship must rota
Aleks04 [339]

Answer:

I don't know this for sure, but I think its because they need to be able to sit in their seats without flying in the air.

Explanation:

3 0
3 years ago
If the mass of an object is 14 lbm, what is its weight, in lbf, at a location where g = 32.0 ft/s2?
mixas84 [53]

Using the formula:

w = m x g ....... eq1

here w is weight of the object.

m is mass of the object, and

g is the acceleration of gravity.

mass, m = 14 lbm (given)

acceleration of gravity, g= 32.0 ft/s^{2}

Now, substituting the values in equation (1):

w = 14lbm x 32.0 ft/s^{2} = 448 lbm ft/s^{2}

since, 1 lbf = 32.174 lbm ft/s^{2}

so, w = 448 x \frac{1}{32.174}

w = 13.924lbf

Hence, the mass of an object is 13.924 lbf.

To know more about such questions, visit:

brainly.com/question/10936674

#SPJ4

3 0
2 years ago
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