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3 years ago

When helping someone whose car has a "dead" battery, how should your car's battery be connected in relation to the dead battery?

Physics

1 answer:

leonid [27]3 years ago

8 0

Positive terminal with Positive terminal. The negative terminal should be connected to the car chassis.

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Different kinds of substances have different properties of metals

bagirrra123 [75]

Answer:

if this is a true or false question then it is true.

Explanation:

6 0

3 years ago

Consider the motion of a 4.00-kg particle that moves with potential energy given by U(x) = + a) Suppose the particle is moving w

gtnhenbr [62]

Correct question:

Consider the motion of a 4.00-kg particle that moves with potential energy given by

$U(x) = \frac{(2.0 Jm)}{x}+ \frac{(4.0 Jm^2)}{x^2}$

a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?

b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?

Answer:

a) 3.33 m/s

b) 0.016 N

Explanation:

a) given:

V = 3.00 m/s

x1 = 1.00 m

x = 5.00

$u(x) = \frac{-2}{x} + \frac{4}{x^2}$

At x = 1.00 m

$u(1) = \frac{-2}{1} + \frac{4}{1^2}$

= 4J

Kinetic energy = (1/2)mv²

$= \frac{1}{2} * 4(3)^2$

= 18J

Total energy will be =

4J + 18J = 22J

At x = 5

$u(5) = \frac{-2}{5} + \frac{4}{5^2}$

$= \frac{4-10}{25} = \frac{-6}{25} J$

= -0.24J

Kinetic energy =

$\frac{1}{2} * 4Vf^2$

= 2Vf²

Total energy =

2Vf² - 0.024

Using conservation of energy,

Initial total energy = final total energy

22 = 2Vf² - 0.24

Vf² = (22+0.24) / 2

$Vf = \sqrt{frac{22.4}{2}$

= 3.33 m/s

b) magnitude of force when x = 5.0m

$u(x) = \frac{-2}{x} + \frac{4}{x^2}$

$\frac{-du(x)}{dx} = \frac{-d}{dx} [\frac{-2}{x}+ \frac{4}{x^2}$

$= \frac{2}{x^2} - \frac{8}{x^3}$

At x = 5.0 m

$\frac{2}{5^2} - \frac{8}{5^3}$

$F = \frac{2}{25} - \frac{8}{125}$

= 0.016N

8 0

4 years ago

A roller coaster speeds up with constant acceleration for 2.3 s until it reaches a velocity of 35 m/s. During this time, the rol

Goshia [24]

Answer:

0.65 m/s

Explanation:

Applying the equation,

v = u + at

35 = u + a×2.3 -(1)

Again, applying the equation,

s = ut + $\frac{1}{2}$ a $t^{2}$

41 = u×2.3 + $\frac{1}{2}$ × $(2.3)^{2}$

35.65 = 2u + 2.3a -(2)

comparing first and second we get u= 0.65 m/s

3 0

3 years ago

A. What are the three longest wavelengths for standing waves on a 240-cm-long string that is fixed at both ends?

vovangra [49]

Answer:

a) the three longest wavelengths = 4.8m, 2.4m, 1.6m

b) what is the frequency of the third-longest wavelength = 75Hz

Explanation:

The steps and appropriate formula and substitution is as shown in the attached file.

5 0

3 years ago

Find the x-component of this

Sholpan [36]

Answer: 74.8m

Explanation:

We have the vector defined by:

r = 101m

θ = 42.2°

When we want to write this as rectangular components, we have that:

x = r*cos(θ)

y = t*sin(θ)

this is because we can construct a triangle rectangle, where the module of the vector is the hypotenuse, the x component is the adjacent cathetus and the y component is the opposite cathetus.

Then, here we have that the x component is

x = 101m*cos(42.2°) = 74.8m

5 0

3 years ago