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ikadub [295]
3 years ago
12

3. The atmospheres of Mars and Venus are mostly carbon dioxide. Earth'satmosphere contains only a fraction of a percent of carbo

n dioxide. Whyis Earth's atmosphere so different from those of Mars and Venus?
Physics
1 answer:
maria [59]3 years ago
3 0

Answer:

Earth's atmosphere is a mixture of nitrogen (79%), oxygen (20%), and a small fraction of carbon dioxide, water vapours and other gases. However, the atmospheres on Venus and Mars mainly consist of carbon dioxide.

Explanation:

You might be interested in
Why does the moon's gravity have a greater effect on the earth's ocean than the sun.
White raven [17]

Answer:

Tides on our planet are caused by the gravitational pull of the Moon and Sun. Earth's oceans "bulge out" because the Moon's gravity pulls a little harder on one side of our planet (the side closer to the Moon) than it does on the other. The Sun's gravity raises tides, too, but lunar tides are twice as big.

4 0
3 years ago
Melvin is traveling south on I-95 at 29 m/s (65 mph) when a deer jumps into his path, 50 m ahead. a. If his reaction time is 0.1
aleksandr82 [10.1K]

Answer:

a. 5.22 meters

b. 2.9 seconds

c. No, Melvin does not hit the deer

Explanation:

The parameters with which Melvin is travelling are as follows;

The speed of Melvin's motion, u = 29 m/s

The distance from Melvin at which the deer jumps into the path = 50 m

a. Distance, d = Velocity, u × Time, t

The time it takes Melvin to react = 0.18 seconds

The distance, "d₁" Melvin travels before his foot hits the break = The velocity with which Melvin was traveling, "u" × The time duration it takes Melvin to hit the brakes, "t₁"

∴ d₁ = 29 m/s × 0.18 s = 5.22 m

The distance, Melvin travels before his foot hits the break = d₁ = 5.22 m

b. Melvin's acceleration after his foot hits the brakes, a = -10 m/s²

Therefore, we have;

The time it takes "t₂" it takes for him to come to a complete stop given as follows;

y = u + a × t₂

Where;

v = The final velocity after Melvin comes to a complete stop = 0 m/s

By substituting the known values, we have;

0 = 29 m/s + (-10 m/s²) × t₂ = 29 m/s - 10 m/s² × t₂

∴ 29 m/s = 10 m/s² × t₂

t₂ = (29 m/s)/(10 m/s²) = 2.9 s

The time it takes it takes for him to come to a complete stop = t₂ = 2.9 s

c. The distance, "d₂", Melvin reaches while accelerating (decelerating) at -10 m/s² to come to a complete stop is given as follows;

v² = u² + 2·a·d₂

Therefore, we have;

0² = (29 m/s)² + 2 × (-10 m/s) × d₂ = (29 m/s)² - 2 × 10 m/s × d₂

∴  (29 m/s)² = 2 × 10 m/s × d₂

d₂ = ((29 m/s)²)/(2 × 10 m/s²) = (841 m²/s²)/(20 m/s²) = 42.05 m

The distance, Melvin reaches while accelerating (decelerating) at -10 m/s² to come to a complete stop = d₂ = 42.05 m

Given that d₂ = 42.05 m < 50 m (The distance separating Melvin's initial location and the deer, Melvin does not hit the deer.

3 0
3 years ago
How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to
finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is x=\sqrt{\frac{2\times EPE}{k}}

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

EPE=\frac{1}{2}kx^2

Rewriting the above expression in terms of 'x', we get:

x=\sqrt{\frac{2\times EPE}{k}}

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m

Therefore, the stretch in the spring is 10 m.

So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.

6 0
3 years ago
A basketball is thrown horizontally with an initial speed of
storchak [24]

Answer:

1.35 m

Explanation:

Taking down to be positive, given:

Δx = Δy / tan 30.0º

v₀ₓ = 4.50 m/s

v₀ᵧ = 0 m/s

aₓ = 0 m/s²

aᵧ = 10 m/s²

Find: Δy

First, find the time it takes to land in terms of Δy.

Δy = v₀ t + ½ at²

Δy = (0 m/s) t + ½ (10 m/s) t²

Δy = 5t²

Next, find Δx in terms of t.

Δx = v₀ t + ½ at²

Δx = (4.50 m/s) t + ½ (0 m/s) t²

Δx = 4.50t

Substitute:

Δy = 5 (Δx / 4.50)²

20.25 Δy = 5 (Δx)²

4.05 Δy = (Δx)²

4.05 Δy = (Δy / tan 30.0º)²

4.05 Δy = 3 (Δy)²

1.35 = Δy

The basketball was thrown from an initial height of 1.35 m.

Graph: desmos.com/calculator/ujuzdo9xpr

8 0
3 years ago
When Jacob bats a baseball with a net force of 4.719 N, it accelerates 33 m/s2. What is the mass of the baseball?
Natasha2012 [34]

Answer:

its 24

Explanation:

5 0
3 years ago
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