Answer:
1) ∠A=84°
2) ∠C=20°
Step-by-step explanation:
1)
First, find ∠C:
<em>(I'm assuming the exterior angle of 126° makes a straight line with ∠C)</em>
The angles on a straight line always add up to 180. Therefore:
∠C+126=180
∠C=180-126
∠C=54
Then find ∠B:
We also know that all the angles in a triangle add up to 180. Therefore:
∠A+∠B+∠C=180
∠A+∠B+54=180
∠A+∠B=126
<em>(we know ∠A=2(∠B))</em>
2(∠B)+∠B=126
3(∠B)=126
∠B=42
Now, find ∠A:
∠A=2(∠B)
∠A=2(42)
∠A=84°
2)
First, find ∠B:
<em>(Again, I'm assuming the exterior angle of 100° makes a straight line with ∠B)</em>
The angles on a straight line always add up to 180. Therefore:
∠B+100=180
∠B=180-100
∠B=80
Then find ∠A:
We also know that all the angles in a triangle add up to 180. Therefore:
∠A+∠B+∠C=180
∠A+80+∠C=180
∠A+∠C=100
<em>(we know ∠A=4(∠C))</em>
4(∠C)+∠C=100
5(∠C)=100
∠C=20°
The answer to the question
Answer:
to organize bivariate data
to plot points to two sets of data
to compare dependent and independent variables
to visualize relationships between
Step-by-step explanation:
Answer:
2 non real solutions.
Step-by-step explanation:
We need to use discriminant,
for ax²+bx+c=0
The discriminat is b²-4ac
If the discriminant is,
→ less than 0, then 0 real solutions
→ equal to 0, then 1 real solutions
→ more than 0, then 2 real solutions
Given that,
7x²−4x+3=0
a=7, b=-4, and c=3
→ (-4)²-4(7)(3)
→ 16-84
→ -68
You can see this is less than 0, then non real solutions. [2 nonreal solutions]
50 percent is the probability
