Answer:
raise a product to a power.
you first simplify the parenthesis in the numerator by raising 2 by the power of three and multiplying the exponents.
i suck at explaining, but after the first step the expression looks like:

Step-by-step explanation:
Answer:
a) There is a 66.7% chance that you were given box 1
b) There is a 80% chance that you were given box 1
Step-by-step explanation:
To find this, we need to note that there is a 1/10 chance of getting a defective bulb with box 1 and a 1/20 chance in box 2.
a) To find the answer to this, find the probability of getting a defective bulb for each box. Since there is only one bulb pulled in this example, we just use the base numbers given.
Box 1 = 1/10
Box 2 = 1/2
From this we can see that Box 1 is twice as likely that you get a defective bulb. As a result, the percentage chance would be 2/3 or 66.7%
b) For this answer, we need to square each of the probabilities in order to get the probability of getting a defective one twice.
Box 1 = 1/10^2 = 1/100
Box 2 = 1/20^2 = 1/400
As a result, Box 1 is four times more likely. This means that it would be a 4/5 chance and have a probability of 80%
Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.