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3 years ago

A person is standing on top of a cliff and falls down. If he takes 3.7 s to hit the ground, how high up is the cliff?

Physics

1 answer:

Maksim231197 [3]3 years ago

7 0

Answer:

h = 67.081 m

Explanation:

Given that,

The time taken by a person to fall down is, t = 2.2 s

The height of the cliff from the ground, h = ?

The distance that the person will fall through the time is given by the formula

S = 1/2 gt² m

Where,

g - acceleration due to gravity

Substituting the values in the above equation

S = 1/2 x 9.8 m/s² x (3.7 s)²

= 67.081 m

Therefore, the height of the cliff from the ground is, h = 67.081 m

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