Answer:
The correct option is;
Absolute zero
Explanation:
A Bose-Einstein condensate is known as the fifth state of matter which is made of a collection of ultra cooled atoms (at almost absolute zero degrees -273.15 °C) such that the there is very slight free energy within the atoms which results in almost no relative motion between the atoms. The atoms then combine forming clumps such that phenomena usually observed at the microscopic level such as wavefunction interference become observable at the microscopic level.
Answer:
Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it 
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:
Now substitute the given values
So
Answer:
B = ρ g V_liquid
the thrust is proportional to the density of the liquid
Explanation:
The density of a liquid is defined as the relationship between the mass and the volume of the liquid
ρ = m / V
The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid
B = W_liquid
B = m _liquid g
we substitute mass for density
B = ρ g V_liquid
therefore we see that the thrust is proportional to the density of the liquid
Answer:
650 km/hr
Explanation:
Draw a right triangle from (0.0) (Point A) down 30 degrees and to the right for a length of 750 (Point B). Then draw a line from B up to the x axis to make a right angle (Point C). Use the cosine function to find line AC, the vector portion of AB that lies of the x (East) axis. Cosine(30)= Adjacent/Hypotenuse.
Cos(30) = AC/750
750*(cos(30)) = AC
AC = 649.5 km/hr
We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:
Vf² = Vi² + 2ad
Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.
Given values:
Vi = 0m/s (dumbbell starts falling from rest)
a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)
d = 80×10⁻²m
Plug in the values and solve for Vf:
Vf² = 2(10)(80×10⁻²)
Vf = ±4m/s
Reject the negative root.
Vf = 4m/s
The momentum of the dumbbell is given by:
p = mv
p is its momentum, m is its mass, and v is its velocity.
Given values:
m = 10kg
v = 4m/s (from previous calculation)
Plug in the values and solve for p:
p = 10(4)
p = 40kg×m/s
