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velikii [3]
3 years ago
9

Tiesha enjoys reading in her spare time. She reads 4 pages every 1/10 of an hour.

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0
Answer: p=40h



Explanation I know
dangina [55]3 years ago
6 0

Answer:

p = 40h

Step-by-step explanation:

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Jason baked 4 pans of brownies. He gave 1/4 of the brownies to his two sisters. How many pans of brownies did he give to his sis
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Jason gave his sisters 1/4 of a pan of brownies to his sister he has three and three fourths left
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2 years ago
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Answer, please. I need help.
kumpel [21]

Answer:

2i, if you don't understand any of the steps let me know, I'd be happy to explain.

Step-by-step explanation:

\sqrt{-x} =\sqrt{-1*x} ,\sqrt{xy}=\sqrt{x} \sqrt{y},   \sqrt{-1}=i

so in order -4 = -1 * 4 so then \sqrt{-1*4}=\sqrt{-1} \sqrt{4} then just solve each

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2 years ago
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Helpppppp me pleaseeeeeee!!!!!!!!
Nimfa-mama [501]

Answer:

Step-by-step explanation:

think of the flight of a small rocket..  what does it seem like the parabola would look like?  down means it looks like a cup or glass , upside down , up mean a cup or glass right side up.

when t = 0  the rocket is at 25, so that's the initial height

it's velocity is initially 200 m/s

put equation from std. form to vertex form

y = ax^{2} + bx +c       =>       y = a(x - h ) ^2 + k

h = -4.9t^{2} + 200t + 25  =>h = -4.9(t - 20.41)^2 + 2,065.82

(h,k) =  (20.41 , 2065.82)

3 0
3 years ago
A go-cart with a mass of 200 kg is pushed with a force of 1000 N (1000 kg m/s2). What is the acceleration of the go-cart? ​
Hunter-Best [27]

Answer:

Acceleration=5m/s^2

Step-by-step explanation:

F=ma

1000=200xa

a=1000/200

a=5m/s^2

8 0
3 years ago
The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims
kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is \mu=600, we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it \sigma) is

\sigma=48

Next they draw a random sample of n=70 students, and they got a mean score (denoted by \bar x) of \bar x=613

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis H_0:\bar x \geq \mu

- The alternative would be then the opposite H_0:\bar x < \mu

The test statistic for this type of test takes the form

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\

<h3>since 2.266>1.645 we  can reject the null hypothesis.</h3>
6 0
3 years ago
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