Answer:
a) the development of infrastructure to support enterprise-wide analytics.
Explanation:
Base on the scenario been described in the question, the type of implementation data where house to collected for the betterment of the company, this is an typical of the development of infrastructure to support enterprise wide range of analytic data collection, building of this infrastructure also help them more physical infrastructure. Option a is the correct answer.
Answer and Explanation:
The computation is shown below:
a. The manufacturing overhead is
= factory utilities + depreciation on factory equipment + indirect factory labor + indirect material + factory manager salary + property tax + factory repairs
= $16,500 + $12,650 + $48,900 + $70,800 + $8,000 + $2,500 + $2,000
= $161,350
b. The product cost is
= Direct material used + direct labor + total manufacturing overhead
= $157,600 + $79,100 + $161,350
= $398,050
c. The period cost is
= Depreciation on delivery truck + sales salaries + repairs to office equipment + advertising + office supplies used
= $3,800 + $48,400 + $1,300 + $23,000 + $4,640
= $81,140
Answer: Enron
Explanation:
Enron scandal was an accounting scandal that involved Enron Corporation, which was an American energy company that was based in Houston, Texas.
Enron hid huge amount of trading losses, which led to its bankruptcy. The company used fraudulent accounting practices in order to inflate the revenue of the company and.hid the debt that the company incurred.
Answer:
C. 1.40x
Explanation:
1. Production:
November through February: x rakes/month* 4 months = 4x rakes.
2. Shipping and storage costs
March= 4x (initial stock) - x/2 (shipped) = 3.5 x (in stock) * 0.1$ = $0.35
April = 3.5x (stock at end of March) - x/2 (shipped) = 3x*0.1$ = $0.30
May = 3x (stock at the end of April) - x/2 (shipped) = 2.5x*0.1$ = $0.25
June= 2.5x (stock at the end of May) - x/2 (shipped) = 2x (in stock) * $0.1 = 0.2$
July = 2x (stock at end of June) - x/2 (shipped) = 1.5x*0.1$ = $0.15
August = 1.5x (stock at the end of July) - x/2 (shipped) = 1x*0.1$ = $0.1
Sept= 1x (stock at the end of August.) - x/2 (shipped) = 0.5 x (in stock) * $0.1 = $0.05
October = 0.5x (stock at end of sept.) - x/2 (shipped) = 0*$0.1 = $0
Total storage cost= $0.35x+$0.30x+$0.25x+$0.20x+$0.15x+$0.10x+$0.05x+$0x
Total storage cost = $1.40X
