Given:
Positions of two artifacts are at points (1, 4) and (5, 2).
To find:
The distance between these two artifacts.
Solution:
Distance formula: The distance between two points is
Using distance formula, the distance between two points (1, 4) and (5, 2) is
Round to the nearest tenth of a unit.
Therefore, the distance between two artifacts is 4.5 units.
Answer:
f(x+2) = 3(x+2)^2 + 2(x+2 + 1
Step-by-step explanation:
you need to replace the x with x+2
So the actual meal was at most 130 dollars they paid minus the 20 dolars tip: 130-20=110 dollars.
it was 5 people: Dolores+5 friends, who presumably all paid the same (buffet).
then we have to divide the 110 among the 5 people: it's 110/5=22
so each of them paid at most 22 dollars:
x (the amount they paid)≤22
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
To learn more about the probability distribution visit:
brainly.com/question/24756209
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There are 4 choose 3 ways to hold 3 kings and 4 possible queens to make up the fourth card of the hand out of a total of 54 choose 4 possible four-card hands, which gives us the following expression for the probability of being dealt 3 kings and a queen out of 4 cards: Or roughly 1 in every 16920 four card hands.
